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azamat
3 years ago
15

Determine the intercepts of the line

Mathematics
1 answer:
aleksklad [387]3 years ago
6 0

Answer:

y-intercept:  (0,5); x-intercept:  (5/2, 0)

Step-by-step explanation:

The equation of the line is given:  -4x + 7 = 2y - 3.

To find the x-intercept, set y = 0 and solve for x:

-4x + 7 = 0 - 3.  This becomes -4x = -10, or x = 5/2.  The x-intercept is (5/2, 0).

To find the y-inercept, set x = 0 and solve for y:

0 + 7 = 2y - 3, or 2y = 10, or y = 5.  Then the y-intercept is (0, 5).

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69,78!!

Step-by-step explanation:

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Lisa [10]

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Step-by-step explanation:

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valentina_108 [34]

Answer:

x =1 for the first problem

and for second question

Step-by-step explanation:

Let's solve your inequality step-by-step.

|2x+5|>0.5

Solve Absolute Value.

|2x+5|>0.5

We know either2x+5>0.5or2x+5<−0.5

2x+5>0.5(Possibility 1)

2x+5−5>0.5−5(Subtract 5 from both sides)

2x>−4.5

2x2>−4.52(Divide both sides by 2)

x>−2.25

2x+5<−0.5(Possibility 2)

2x+5−5<−0.5−5(Subtract 5 from both sides)

2x<−5.5

2x2<−5.52(Divide both sides by 2)

x<−2.75

Answer:

x>−2.25 or x<−2.75

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2 years ago
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Answer:

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Step-by-step explanation:


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3 years ago
Read 2 more answers
The rate of transmission in a telegraph cable is observed to be proportional to x2ln(1/x) where x is the ratio of the radius of
sergij07 [2.7K]

Answer:

The value of x that gives the maximum transmission is 1/√e ≅0.607

Step-by-step explanation:

Lets call f the rate function f. Note that f(x) = k * x^2ln(1/x), where k is a positive constant (this is because f is proportional to the other expression). In order to compute the maximum of f in (0,1), we derivate f, using the product rule.

f'(x) = k*((x^2)'*ln(1/x) + x^2*(ln(1/x)')) = k*(2x\,ln(1/x)+x^2*(\frac{1}{1/x}*(-\frac{1}{x^2})))\\= k * (2x \, ln(1/x)-x)

We need to equalize f' to 0

  • k*(2x ln(1/x) - x) = 0 -------- We send k dividing to the other side
  • 2x ln(1/x) - x = 0 -------- Now we take the x and move it to the other side
  • 2x ln(1/x) = x -- Now, we send 2x dividing (note that x>0, so we can divide)
  • ln(1/x) = x/2x = 1/2 -------  we send the natural logarithm as exp
  • 1/x = e^(1/2)
  • x = 1/e^(1/2) = 1/√e ≅ 0.607

Thus, the value of x that gives the maximum transmission is 1/√e.

7 0
3 years ago
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