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3 years ago

A chemical company is considering two processes

Mathematics

1 answer:

zhannawk [14.2K]3 years ago

8 0

Answer: $166.430 per year

Step-by-step explanation:

0= -900000+AOC(P/A, 40%,3)

0= -900000+AOC(1.5889)

result we get

AOC= $566430

Require reduction = 566430-400000

result we get

$166.430 per year

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Help please just answer would be fine

scZoUnD [109]

The amount of water decreases $16\frac{1}{2}$ pints in 12 weeks.

Solution:

The amount of water decreases in 7 weeks = $9\frac{5}{8}$ pints

The amount of water decreases each week is same.

Let us first change the mixed fraction into improper fraction.

$9\frac{5}{8}$ pints = $\frac{(9\times8)+5}{8}$

$=\frac{77}{8}$ pints

The amount of water decreases in 1 week

$$=\frac{\frac{77}{8} }{7}$

$=\frac{77}{8\times7}$

$=\frac{11}{8}$

So, the amount of water decreases in 1 week is $\frac{11}{8}$ pints.

The amount of water decreases in 12 week

$=\frac{11}{8}\times12$

$=\frac{132}{8}$

$=16\frac{4}{8}$

$=16\frac{1}{2}$ pints

Hence the amount of water decreases $16\frac{1}{2}$ pints in 12 weeks.

4 0

3 years ago

Find the area of the shape below. Break<br> the larger shape into smaller pieces if needed.

NikAS [45]

Answer:

116 Sq inches

Step-by-step explanation:

3×area of rectangle (l× b) + 2 area of triangle (1/2 b h)

3×32 + 2×1/2×4×5

96 + 20

116

5 0

2 years ago

If i have 2 snickers and my friend takes one what would I have left?

Sauron [17]

Answer:

Step-by-step explanation:

5 0

3 years ago

What is the probability that 1 or 2 are rolled on a number cube with sides numbered 1, 2, 3, 4,

choli [55]

Answer: $\frac{1}{3}$

Step-by-step explanation:

total sides = 6

p (rolling a 1) = $\frac{1}{6}$

p (rolling a 2) = $\frac{1}{6\\}$

Note:

or - add

and - multiply

∴ $\frac{1}{6} +\frac{1}{6} = \frac{2}{6}$

∴ $\frac{2}{6} = \frac{1}{3}$

hence, p (rolling a 1 or 2) = $\frac{1}{3}$

4 0

2 years ago

If x^2+1/x^2=3 find the value of x^2/(x^2+1)^2<br> Express answer as a common fraction.<br> Thanks!!

timama [110]

$x^2+\dfrac1{x^2}=3\implies x^4+1=3x^2\implies x^4-3x^2+1=0$

By the quadratic formula,

$x^2=\dfrac{3\pm\sqrt5}2\implies x^2+1=\dfrac{5\pm\sqrt5}2$

Then

$(x^2+1)^2=\dfrac{25\pm10\sqrt5+5}4=\dfrac{15\pm5\sqrt5}2$

$\implies\dfrac{x^2}{(x^2+1)^2}=\dfrac{\frac{3\pm\sqrt5}2}{\frac{15\pm5\sqrt5}2}=\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}$

Multiply numerator and denominator by the denominator's conjugate:

$\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}\cdot\dfrac{15\mp5\sqrt5}{15\mp5\sqrt5}=\dfrac{45\pm15\sqrt5\mp15\sqrt5-25}{15^2-(5\sqrt5)^2}=\dfrac{20}{100}=\dfrac15$

3 0

3 years ago