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ira [324]
2 years ago
8

In a right ABC with B and C complementary, sin B = p and cos B = q. What is sin C – cos C?

Mathematics
1 answer:
inna [77]2 years ago
7 0

9514 1404 393

Answer:

  q - p

Step-by-step explanation:

For complementary angles B and C, ...

  cos(C) = sin(B) = p

  sin(C) = cos(B) = q

Then the difference is ...

  sin(C) -cos(C) = q - p

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What do you want to calculate?

CALCULATE IT!
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Problem:
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8
y
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Steps:
I will solve your system by substitution.
(You can also solve this system by elimination.)
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x
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y
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−
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y
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y
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x
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2
y
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18
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20
(Simplify both sides of the equation)
2
y
−
18
+
18
=
−
20
+
18
(Add 18 to both sides)
2
y
=
−
2
2
y
2
=
−
2
2
(Divide both sides by 2)
y
=
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1
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1
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x
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2
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y
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(
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3 0
3 years ago
How do you do this question?
Hitman42 [59]

The central angle corresponding to AOB is half of the 8pi/9 radians mentioned, meaning that the central angle of AOB is 4pi/9.

Converting that to degrees:

4pi/9 180 degrees

-------- * -------------------- = 80 degrees.

1 pi

4 0
3 years ago
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