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Citrus2011 [14]
3 years ago
7

Find the area of a rectangle that is 16 3/5in. by 8 9/10

Mathematics
1 answer:
Alenkinab [10]3 years ago
8 0
<h2>Greetings!</h2>

Answer:

Area is 147.74

Step-by-step explanation:

You need to recall that the equation for the area of a rectangle is:

Length * Width = area

So 16 3/5 * 8 9/10 = area

Rearrange so the whole numbers are being multiplied and the fractions are too:

We need to make the denominator same, this can be done by simply multiplying 3/5 by 2:

3/5 * 2 = 6/10

Now the two numbers can be written as 16.6 and 8.9.

Multiply both numbers by 10:

166 * 89 = 14774

Then divide this by 100 (two lots of division by 10)

14774 ÷ 1000 = 147.74

So the area of the rectangle is 147.74!


<h2>Hope this helps!</h2>
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Given the equation 4x2 − 8x + 20 = 0, what are the values of h and k when the equation is written in vertex form a(x − h)2 + k =
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Answer:

The correct option is:

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Step-by-step explanation:

y=4x^2-8x+20 =0

It is a quadratic formula in standard form:

ax^2+bx+c

where a = 4 , b = -8 and c=20

The vertex form is:

a(x − h)2 + k = 0

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Substitute k for y and insert the value of h for x in the standard form:

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