We know that m<JKL = m<JKM + m<MKL
Let's substitute the values from the picture into our equation above.
10x - 11 = 43 + 8x - 20
Combine like terms.
10x - 11 = 8x + 23
Subtract 8x from both sides and add 11 to both sides.
2x = 34
Divide both sides by 2
x = 17
m<MKL = 8x - 20 = 8(17) - 20 = 136 - 20 = 116 degrees.
m<JKL = 10x - 11 = 10(17) - 11 = 170 - 11 = 159 degrees.
Answer:
yg yc8ggt 8tycg6ctg7t6gt
Step-by-step explanation:
gygc86gc688rc6iycrgciutv
<span>Lets say the 1st die rolled a 2 -
there would be 2 combinations for which the sum of dice being < 5 :
2,1
2,2
Now say the 2nd die rolled a 2 -
there would be 2 combinations for which the sum of dice being < 5 :
1,2
2,2
Now we want to count all cases where either dice showed a 2 and sum of the dice was < 5. However note above that the roll (2,2) is counted twice.
So there are three unique dice roll combinations which answer the criteria of at least one die showing 2, and sum of dice < 5:
1,2
2,1
2,2
The total number of unique outcomes for two dice is 6*6=36 .
So, the probability you are looking for is 3/36 = 1/12</span>
Answer:
Hmm. I'm not sure... But I just wanted to say I love your profile picture.
Step-by-step explanation:
