X+12x-13 = 0 and azo, what<br>is the value x+lo?

alina1380 [7]

When the dice is rolled 14 times then from the given data the probability of 1,2,3,4,5,6 is 3/14,1/14,4/14,1/14,3/14,2,14.

Given Roll of dice and outcomes from 1 to 14 is 1,3,5,4,5,3,3,1,3,5,6,1,6,2.

From the given collected data we can find out number of times each number came when the dice is rolled.

Number of times 1 came=3

Number of times 2 came=1

Number of times 3 came=4

Number of times 4 came=1

Number of times 5 came=3

Number of times 6 came=2

The probabilities are in fraction form:

P(1)=3/14

P(2)=1/14

P(3)=4/14

P(4)=1/14

P(5)=3/14

P(6)=2/14

The probabilities in decimal form:

P(1)=0.21

P(2)=0.07

P(3)=0.28

P(4)=0.07

P(5)=0.21

P(6)=0.14

The probabilities in percentage:

P(1)=21%

P(2)=7%

P(3)=28%

P(4)=7%

P(5)=21%

P(6)=14%

Hence the probabilities are 3/14,1/14,4/14,1/14,3/14,2,14.

Learn more about probabilities here brainly.com/question/24756209

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5 0

2 years ago

A particle moves along a line with acceleration a (t) = -1/(t+2)2 ft/sec2. Find the distance traveled by the particle during the

amm1812

Answer:

$s(t)=(ln|7|+ln|2|)\,ft$

Step-by-step explanation:

Acceleration is second derivative of distance and are related as:

$a(t)=\frac{d^2s}{dt^2}\\\\\frac{d^2s}{dt^2}=\frac{-1}{(t+2)^2}\\$

Integrating both sides w.r.to t

$v(t)=\frac{ds}{dt}=\frac{1}{t+2} +C\\$

Using initial value

$v(0)=\frac{1}{2}\\\\\frac{1}{2}=\frac{1}{0+2} +C\\\\C=0\\\\\frac{ds}{dt}=\frac{1}{t+2}$

We have to calculate the distance covered in time interval [0,5], so:

$\int\limits^5_0 \frac{ds}{dt}=\int\limits^5_0 {\frac{1}{t+2}} \, dt\\\\s(t)=[ln|t+2|]^5_0\\\\s(t)=ln|5+2|+ln|0+2|\\\\s(t)=(ln|7|+ln|2|)\,ft$

3 0

3 years ago

A store sells Brazilian coffee for $10 per lb. and Columbian coffee for $14 per lb. If the store decides to make a 150-lb. blend

Artemon [7]

Answer:

The store should use 112.5 pounds of Brazilian coffee and 37.5 pounds of Colombian cofee.

Step-by-step explanation:

Let "b" be the amount of Brazilian coffee, in pounds, required for the blend and "c" the amount of Colombian coffee required, in pounds.

Since there are two unknown variables a two-equation system is needed to solve the problem, we can set up one equation for weight and another for price as follows:

$b+c=150\\10*b+14*c=11*150$

Solve for "c" by multiplying the first equation by -10 and adding it to the second one:

$b+c=150\\10b+14c -10b-10c=11*150 -(10*150)\\4c=150\\c = 37.5$

Now, solve for b by replacing the value obtained into the first equation

$b+c=150\\b= 150 - 37.5\\b=112.5$

The store should use 112.5 pounds of Brazilian coffee and 37.5 pounds of Colombian cofee.

6 0

3 years ago

For all pairs of real numbers N and P, where N =5P+ 4, p=? Please help!!!!

drek231 [11]

N = 5P + 4
N - 4 = 5P
(N - 4) / 5 = P or (N/5) - 4/5 = P

4 0

3 years ago

Evaluate 2•4-8 divided by 4

Vaselesa [24]

Answer:

Step-by-step explanation:

Answer and work are in picture below.

4 0

3 years ago

X+12x-13 = 0 and azo, whatis the value x+lo?​

X+12x-13 = 0 and azo, whatis the value x+lo?