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goldfiish [28.3K]
3 years ago
8

X+12x-13 = 0 and azo, whatis the value x+lo?​

Mathematics
1 answer:
Andru [333]3 years ago
5 0
Wat this doesn’t make sense
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A 6-pack of batteries cost $10.50.what is the unit price
IRINA_888 [86]

Answer:

Unit price = $1.75

Step-by-step explanation:

In order to determine the unit price of the batteries, divide the $10.50 total price for the 6-pack of batteries by 6:

$10.50 ÷ 6 = $1.75

Therefore, the unit price of each battery is $1.75.

4 0
3 years ago
Read 2 more answers
Nine years ago, Tarah opened a savings account with her bank. She started with a balance of $359 and has not made any withdrawal
Nikitich [7]

Answer: They should have like $100.52 Or something I’m assuming

Step-by-step explanation: I’m doing this to finish the 3 steps for this website and I have no idea what this is. So like she has $359, pays 8% interest for 9 years, 359 x 0.08 x 9 or however, someone else who’s a pro do this.

8 0
3 years ago
A square is shown below. Which expression can be used to find the area, in square units, of the
xz_007 [3.2K]
8 units OA 4.4 2 1 OB 44 oc 8.8 20.4-8-8
8 0
2 years ago
If Rihanna deposite 1500 rupees in the school fund at 9 p.C.P.A for 2 years, what is the total amount she will get?
S_A_V [24]

Answer: 1770 rupees

Step-by-step explanation:

To solve this, we first calculate the simple interest which will be:

= (P × R × T) / 100

= (1500 × 9% × 2) / 100

= (1500 × 0.09 × 2) / 100

= 270

The total amount tha she'll get will be:

= 1500 + 270

= 1770 rupees

3 0
3 years ago
Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.
charle [14.2K]

ANSWER

See below

EXPLANATION

Given

f(x) =  \frac{ {x}- 9 }{x + 5}

and

g(x) =   \frac{ - 5x - 9}{x - 1}

(f \circ \: g)(x)=  \frac{ (\frac{ - 5x - 9}{x - 1})- 9 }{(\frac{ - 5x - 9}{x - 1} )+ 5}

(f \circ \: g)(x)=  \frac{ \frac{ - 5x - 9 - 9(x - 1)}{x - 1}}{\frac{ - 5x - 9 + 5(x - 1)}{x - 1} }

Expand:

(f \circ \: g)(x)=  \frac{ \frac{ - 5x - 9 - 9x  + 9}{x - 1}}{\frac{ - 5x - 9 + 5x - 5}{x - 1} }

(f \circ \: g)(x)=  \frac{ \frac{ - 5x - 9x  + 9 - 9}{x - 1}}{\frac{ - 5x + 5x - 5 - 9}{x - 1} }

(f \circ \: g)(x)=  \frac{ \frac{ - 14x }{x - 1}}{\frac{ -14}{x - 1} }

Since the denominators are the same, they will cancel out,

(f \circ \: g)(x)= \frac{ - 14x}{ - 14}  = x

8 0
3 years ago
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