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3 years ago

Please help this is due today!!

Mathematics

1 answer:

WITCHER [35]3 years ago

8 0

24 is the answer hip hop horsy

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PLEASE ANSWER ASAP! AN EXPLANATION IS A MUST REQUIREMENT IN ORDER TO RECEIVE 10 POINTS AND THE BRAINLIEST ANSWER! THANKS!!!

Rina8888 [55]

Hello,
In a Venn 's diagram: A={Custumer edu},B={french}, U=the class.

#(A\B)=22-2=20
#(B\A)=20-2=18
#(A∩B)=2
#U=80

p=(20+2+18)/80=20/40=1/2

Answer C (11/40+1/4-1/10=20/40=1/2)

Sorry for the mistake.

6 0

4 years ago

What is the equation of the following graph in vertex form? Courtesy of Texas Instruments A. y = (x − 4)2 − 4 B. y = (x + 4)2 −

Shtirlitz [24]

Answer:

A: y = (x − 4)^2 − 4

Step-by-step explanation:

vertex=(4.-4)

A: y = (x − 4)^2 − 4

y=x^2-8x+16-4

y=x^2-8x+12 (a=1,b=-8,c=12)

the y intercept is (0,12)

vertex ( h, k)

h=-b/2a ⇒ h=-(-8)/2=4

plug the value of h in the equation y=x^2-8x+12

k=4²-8(4)+12

k=16-32+12

k=-4

v(4,-4)

6 0

3 years ago

A bin of 50 manufactured parts contains 3 defective parts and 47 non-defective parts. A sample of size 6 parts is selected from

lyudmila [28]

Answer:

535,095 different samples of size six that contain exactly 2 defective parts.

0.0337 = 3.37% probability that a sample contains exactly 2 defective parts.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

As the order of the parts is not important, the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

How many different samples are there of size six that contain exactly 2 defective parts?

2 defective from a set of 3, and 4 non-defective from a set of 47. So

$D = C_{3,2}*C_{47,4} = \frac{3!}{2!1!}*\frac{47!}{4!43!} = 535095$

535,095 different samples of size six that contain exactly 2 defective parts.

What is the probability that a sample contains exactly 2 defective parts?

The total number of samples is:

$T = C_{50,6} = \frac{50!}{6!44!} = 15890700$

Then...

$p = \frac{D}{T} = \frac{535095}{15890700} = 0.0337$

0.0337 = 3.37% probability that a sample contains exactly 2 defective parts.

8 0

3 years ago

Please help me out, the question is in the image attached.

alexandr1967 [171]

9514 1404 393

Answer:

d = 2.5 ft

Step-by-step explanation:

Similar figures have proportional linear measures.

diameter/height = d/1 = 10/4

d = 5/2 = 2.5 . . . . feet

4 0

3 years ago

C. 6

Goryan [66]

Answer:

6. 10

Step-by-step explanation:

6 0

3 years ago