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3 years ago

What is the value of n? n/-3 - 2 = -18

Mathematics

2 answers:

svp [43]3 years ago

7 0

Answer:

the value of n = -48 .......

SCORPION-xisa [38]3 years ago

4 0

Answer:

Step-by-step explanation:

n/-3=-16

n=-16*-3

n=48

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elixir [45]

Answer:

Step-by-step explanation:

The degree of a polynomial is determined by the largest exponent of a term within the polynomial.

Given

7x³ + 4x - 5 + 8 $x^{5}$

The term with the largest exponent is 8 $x^{5}$ with exponent 5

Thus the polynomial is of degree 5 → D

3 0

3 years ago

CALCULUS - Find the values of in the interval (0,2pi) where the tangent line to the graph of y = sinxcosx is

Rufina [12.5K]

Answer:

$\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}$

Step-by-step explanation:

We want to find the values between the interval (0, 2π) where the tangent line to the graph of y=sin(x)cos(x) is horizontal.

Since the tangent line is horizontal, this means that our derivative at those points are 0.

So, first, let's find the derivative of our function.

$y=\sin(x)\cos(x)$

Take the derivative of both sides with respect to x:

$\frac{d}{dx}[y]=\frac{d}{dx}[\sin(x)\cos(x)]$

We need to use the product rule:

$(uv)'=u'v+uv'$

So, differentiate:

$y'=\frac{d}{dx}[\sin(x)]\cos(x)+\sin(x)\frac{d}{dx}[\cos(x)]$

Evaluate:

$y'=(\cos(x))(\cos(x))+\sin(x)(-\sin(x))$

Simplify:

$y'=\cos^2(x)-\sin^2(x)$

Since our tangent line is horizontal, the slope is 0. So, substitute 0 for y':

$0=\cos^2(x)-\sin^2(x)$

Now, let's solve for x. First, we can use the difference of two squares to obtain:

$0=(\cos(x)-\sin(x))(\cos(x)+\sin(x))$

Zero Product Property:

$0=\cos(x)-\sin(x)\text{ or } 0=\cos(x)+\sin(x)$

Solve for each case.

Case 1:

$0=\cos(x)-\sin(x)$

Add sin(x) to both sides:

$\cos(x)=\sin(x)$

To solve this, we can use the unit circle.

Recall at what points cosine equals sine.

This only happens twice: at π/4 (45°) and at 5π/4 (225°).

At both of these points, both cosine and sine equals √2/2 and -√2/2.

And between the intervals 0 and 2π, these are the only two times that happens.

Case II:

We have:

$0=\cos(x)+\sin(x)$

Subtract sine from both sides:

$\cos(x)=-\sin(x)$

Again, we can use the unit circle. Recall when cosine is the opposite of sine.

Like the previous one, this also happens at the 45°. However, this times, it happens at 3π/4 and 7π/4.

At 3π/4, cosine is -√2/2, and sine is √2/2. If we divide by a negative, we will see that cos(x)=-sin(x).

At 7π/4, cosine is √2/2, and sine is -√2/2, thus making our equation true.

Therefore, our solution set is:

$\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}$

And we're done!

Edit: Small Mistake :)

5 0

3 years ago

I don't get how to work out the repeating problems, could someone explain please?

barxatty [35]

Detecting...

Your answer would be:

$0.025 = 1/40 

0.025/1 * 1000/1000 = 25/1000

25 \div 25 / 1000 \div 25 = 1/40

1/40 is your answer.$

3 0

3 years ago

Simplify. 5y(4x-3z)

Dahasolnce [82]

Answer:

Option D is the right option.

Solution,

 $5y(4x - 3z) \\ = 5y \times 4x - 5y \times 3z \\ = 20xy - 15yz$ 

hope this helps...

Good luck on your assignment...

5 0

3 years ago

Read 2 more answers

Which of the following best represents the relationship between angles A and B?

Readme [11.4K]

Answer:

A = B

Step-by-step explanation:

This is because they are alternate exterior angles and they equal the same thing.

4 0

3 years ago

Read 2 more answers