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natulia [17]
3 years ago
5

Express the vector negative 3 Bold i plus 6 Bold j plus 2 Bold k as a product of its length and direction.

Mathematics
1 answer:
ANTONII [103]3 years ago
6 0

Answer:

A

Step-by-step explanation:

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Graph the equation: x = y^2 - 2
Lesechka [4]
Draw a cartesian plane, create a graph with the equation x = y^2 - 2
then substitute numbers into the equation so that it is true, to find points on the graph, e.g. substitute y with 1, you get 
x = 1^2 - 2
x = 1 - 2 = -1, so when y = 1, x = -1, this point is (-1, 1)

for the next substitute y with 2,
x = 2^2 - 2
x = 4 - 2 = 2, the point is (2, 2)
you might want to try negative values of y 
y = -1, x = (-1)^2 - 2
x = -1 the point is (-1,-1)

then plot the points on the graph
5 0
3 years ago
Raymond has two seven foot long boards, and wants to cut fifteen inch long peices from each; what is the greatest number of peic
anastassius [24]

7ft = 84in   84  ÷  15 =  5.6 pieces he can cut from each board.  Since .6 is not a whole piece measuring 15 inches long, he can only cut 5 pieces from each board.

So, 5 x 2 = 10

He would be able to cut 10 pieces measuring 15 inches long.

Hope this helps :)

7 0
3 years ago
Read 2 more answers
If tan theta = 12/5 and cos theta < 0, what is sin theta ?
Talja [164]
1 + tan ² Ф=sec²Ф
1+(12/5)²=sec²Ф
169/25=sec² Ф
sec Ф=⁺₋√(169/25)=⁺₋13/5

sec Ф=1/cos Ф ⇒cosФ=1/sec Ф
 cos Ф>0   ⇔  sec Ф>0  ⇔  sec Ф=+ 13/5

cos Ф=1/secФ
cos Ф=1 / 13/5=5/13

we can calculate the sin Ф, with this method.
sin²Ф + cos²Ф=1  ⇒ sin Ф=⁺₋√(1-cos² Ф)
sin Ф=⁺₋√[1-(5/13)²]=⁺₋12/13
like cos Ф>0 and tan Ф>0   ⇒ sin Ф>0 ⇒sin Ф=12/13

answer: d.12/13

other method
tan Ф=sin Ф / cos Ф
12/5=sin Ф / 5/13
sin Ф=(12/5)*(5/13)=12/13

answer: d.12/13

8 0
3 years ago
Please help me I need help
MariettaO [177]
The collect 19 boxes by the end of everyday.
8 0
3 years ago
True or false, A function is a relation if and only if the x-values do not repeat in a given set
salantis [7]
Its false because it can't repeat in a set.
5 0
3 years ago
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