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Alenkasestr [34]
2 years ago
5

Predict the precipitate produced by mixing an Al(NO3)3 solution with a KOH solution. Write the net ionic equation for the reacti

on.
Molecular equation:


Complete Ionic Equation:

Net Ionic Equation:

Identify spectator ions:
Chemistry
1 answer:
telo118 [61]2 years ago
8 0

Based on the reactants and products,

  • The molecular equation of the reaction is: Al(NO3)3 + 3 KOH ---> Al(OH)3 + NaNO3
  • The complete ionic equation of the reaction is: Al3+ 3NO3- + 3 K+ 3OH- ---> Al(OH)3(s) + 3 Na+ 3 NO3+
  • The net ionic equation of the reaction is:Al3+ 3OH- ---> Al(OH)3(s)
  • The spectator ions are: Na+ and NO3+

<h3>What is a precipitate?</h3>

A precipitate is a solid product formed in when two solutions of salts react by double replacement.

The molecular equation of the reaction of Al(NO3)3 solution with a KOH solution is:

Al(NO3)3 + 3 KOH ---> Al(OH)3 + NaNO3

The complete ionic equation of the reaction of Al(NO3)3 solution with a KOH solution is:

Al3+ 3NO3- + 3 K+ 3OH- ---> Al(OH)3(s) + 3 Na+ 3 NO3+

The net ionic equation of the reaction of Al(NO3)3 solution with a KOH solution is:

  • Al3+ 3OH- ---> Al(OH)3(s)

  • The spectator ions are: Na+ and NO3+

Learn more about ionic equation at: brainly.com/question/25604204

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The empirical formula of a compound is CH3- The molecular formula of this compound could be C2H6 CH4 C3H6 C2H4
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BH+ClO4- is a salt formed from the base B (Kb = 1.00e-4) and perchloric acid. It dissociates into BH+, a weak acid, and ClO4-, w
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Answer:

The pH of 0.1 M BH⁺ClO₄⁻ solution is <u>5.44</u>

Explanation:

Given: The base dissociation constant: K_{b} = 1 × 10⁻⁴, Concentration of salt: BH⁺ClO₄⁻ = 0.1 M

Also, water dissociation constant: K_{w} = 1 × 10⁻¹⁴

<em><u>The acid dissociation constant </u></em>(K_{a})<em><u> for the weak acid (BH⁺) can be calculated by the equation:</u></em>

K_{a}. K_{b} = K_{w}    

\Rightarrow K_{a} = \frac{K_{w}}{K_{b}}

\Rightarrow K_{a} = \frac{1\times 10^{-14}}{1\times 10^{-4}} = 1\times 10^{-10}

<em><u>Now, the acid dissociation reaction for the weak acid (BH⁺) and the initial concentration and concentration at equilibrium is given as:</u></em>

Reaction involved: BH⁺  +  H₂O  ⇌  B  +  H₃O+

Initial:                     0.1 M                    x         x            

Change:                   -x                      +x       +x

Equilibrium:           0.1 - x                    x         x

<u>The acid dissociation constant: </u>K_{a} = \frac{\left [B \right ] \left [H_{3}O^{+}\right ]}{\left [BH^{+} \right ]} = \frac{(x)(x)}{(0.1 - x)} = \frac{x^{2}}{0.1 - x}

\Rightarrow K_{a} = \frac{x^{2}}{0.1 - x}

\Rightarrow 1\times 10^{-10} = \frac{x^{2}}{0.1 - x}

As, x

\Rightarrow 0.1 - x = 0.1

\therefore 1\times 10^{-10} = \frac{x^{2}}{0.1 }

\Rightarrow x^{2} = (1\times 10^{-10})\times 0.1 = 1\times 10^{-11}

\Rightarrow x = \sqrt{1\times 10^{-11}} = 3.16 \times 10^{-6}

<u>Therefore, the concentration of hydrogen ion: x = 3.6 × 10⁻⁶ M</u>

Now, pH = - ㏒ [H⁺] = - ㏒ (3.6 × 10⁻⁶ M) = 5.44

<u>Therefore, the pH of 0.1 M BH⁺ClO₄⁻ solution is 5.44</u>

5 0
3 years ago
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