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3 years ago

About how many cubes were used to make this figure? A. about 40 B. about 70 C. about 100 D. about 140

Mathematics

1 answer:

natta225 [31]3 years ago

4 0

Answer:

Around 100,i.e. 105

Step-by-step explanation:

In the given cube

Length of the cube = 7 unit cells

Breadth of the cube = 3 unit cells

Height of the cube = 5 unit cells

Therefore the number of unit cubes required to make such big cube is nothing but the volume of the big cube = length*breadth*height

⇒Number of cubes used to make that big cube= 7*5*3

= 105

Hence, option D (around 100) is the correct answer

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kifflom [539]

Answer:

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Step-by-step explanation:

To find the solution of the system of two equations

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equate right sides of these two equations:

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3 years ago

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nasty-shy [4]

Answer:

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Step-by-step explanation:

given data

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in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

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volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

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and we know velocity is express as

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here tension = mg

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

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when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

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T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

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relative density = 2.78 ≈ 2.8

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