If s is the side of the square base, the area of the square base is s^2.
The volume of the square base is,
V = (s²) (h)
s² = V/h
s² = 3n³ + 13n² + 16n + 4 / <span>3n + 1
You can do this division by factoring, synthetic division, or by plain division.
Factoring out 3n + 1 from the numerator gives you:
</span>s² = (3n + 1)(n² + 4n + 4) / 3n+1
s² = n² + 4n + 4
Therefore, the area of the square base is <span>n² + 4n + 4.</span>
Given:
A line passes through (1,-2) and is perpendicular to
.
To find:
The equation of that line.
Solution:
We have, equation of perpendicular line.

Slope of this line is



Product of slope of two perpendicular lines is -1.



Now, slope of required line is
and it passes through (1,-2). So, the equation of line is

where, m is slope.





Therefore, the equation of required line is
.
The answer is 6 cause 9-5 is 4 and 20/4 equal 5+1 equal 6
Cut 5 equal sections from a 2 foot long ribbond