First find the numbers that are divisible by 3.
3, 6, 9, 12, 15, 18, 21, 24
There are 8 numbers divisible by 3 so there are 16 that are not divisible by 3.
P(not div by 3) = 16/24 = 2/3
The straight edge of the semicircle is 4 units, as this is this the diameter.
The circumference of the full circle is
C = pi*d = pi*4 = 4pi
which is the distance around the full circle (aka circle's perimeter)
So half of this is 4pi/2 = 2pi
Add this onto the straight edge length to get 4+2pi as the exact distance around the entire semicircle. This includes both straight and curved portions.
If you use the approximation pi = 3.14, then 4+2*pi = 4+2*3.14 = 10.28 is the approximate answer. To get a more accurate answer, use more decimal digits in pi.
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In summary,
exact answer in terms of pi is 4+2pi units
approximate answer is roughly 10.28 units (using pi = 3.14)
Answer:
6.8% decrease
Step-by-step explanation:
a drop of 8% means that only 92% of 125 boys remained on honor roll from last year; .92 x 125 = 115
a drop of 5% means that only 95% of 80 girls remained on honor roll from last year; .95 x 80 = 76
total number of students on honor roll last year = 125 + 80 = 205
total number of students on honor roll this year = 115 + 76 = 191
percent of change = (191 - 205) ÷ 205 = -14/205 = -.068
-.068, which represents a 6.8% decrease
Answer:
x=-10
Step-by-step explanation:
3x · 3x=9x-11x>20
-2x>20
÷-2 -2
___________-
x=-10
Hope this helps ∞
Answer:
<u>Triangle ABC and triangle MNO</u> are congruent. A <u>Rotation</u> is a single rigid transformation that maps the two congruent triangles.
Step-by-step explanation:
ΔABC has vertices at A(12, 8), B(4,8), and C(4, 14).
- length of AB = √[(12-4)² + (8-8)²] = 8
- length of AC = √[(12-4)² + (8-14)²] = 10
- length of CB = √[(4-4)² + (8-14)²] = 6
ΔMNO has vertices at M(4, 16), N(4,8), and O(-2,8).
- length of MN = √[(4-4)² + (16-8)²] = 8
- length of MO = √[(4+2)² + (16-8)²] = 10
- length of NO = √[(4+2)² + (8-8)²] = 6
Therefore:
and ΔABC ≅ ΔMNO by SSS postulate.
In the picture attached, both triangles are shown. It can be seen that counterclockwise rotation of ΔABC around vertex B would map ΔABC into the ΔMNO.