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SIZIF [17.4K]
4 years ago
8

There are  students in a small class. To make a team, the names of  of them will be drawn from a hat. How many different teams o

f  students are possible?
Mathematics
1 answer:
FromTheMoon [43]4 years ago
8 0
e.g\\a\ small\ class\ has\ 15\ students\ and\ we\ will\ choose\ 3-person\ team\\\\the\ number\ of\ possible\ teams\ is\\\\ {n \choose k}={15 \choose 3}= \frac{15!}{3!\cdot(15-3)!}= \frac{12!\cdot13\cdot14\cdot15}{2\cdot3\cdot12!}  = \frac{13\cdot2\cdot7\cdot3\cdot5}{2\cdot3} = 13\cdot7\cdot5=455
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The cost in dollars of making x items is given by the function C(x)=10x+900 .
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For the given cost equation we have:

a) Fixed cost is $900.

b) For making 25 items the cost is $1150.

c) D: x ∈ [0, 150]

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<h3>Working with the cost equation.</h3>

Here we know that the cost equation is:

c(x) = 10*x + 900.

First, we want to get the fixed cost, it is given by evaluating the function in x = 0.

c(0) = 10*0 + 900 = 900

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b) Now we want to get the cost for making 25 items, to get this, we just evaluate in x = 25.

c(25) = 10*25 + 900 = 250 + 900 = 1150

c) Now, if the maximum cost is 2400, then the maximum number of items that we can make is x₀, such that:

c( x₀) = 2400 = 10*x₀ + 900

Solving for x₀ we get:

x₀ = (2400 - 900)/10 = 150

Now we want to get the range and domain.

We know that we can make between 0 and 150 items, so the domain is:

D: x ∈ [0, 150]

For the range, we know that the fixed cost for 0 items is 900, and the maximum cost is 2400, then the range is:

R: c ∈ [900, 2400]

If you want to learn more about domain and range:

brainly.com/question/10197594

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2 years ago
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Hello,

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4 years ago
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Answer:

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