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Gennadij [26K]
2 years ago
14

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In a certain class, one-third of the students were absent. Half of the total strength attended the Maths test and one-fourth of the total strength attended the Physics test. If 6 students attended both the tests and every student who was present attended at least one of the two tests, then how many students were absent on that day?
\rule{64mm}{3pt}
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\rule{64mm}{4pt}
\large \underline{ \underline{\frak{ Expecting \: answer \: from }}}
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\bull \: \small \red{\rm{ Trusted \: helpers }}
\bull \bull \bull \bull \bull \bull \bull \bull \bull \bull \bull \bull \bull \bull \bull \bull \bull \bull \bull

​
Mathematics
1 answer:
MAVERICK [17]2 years ago
5 0

The number of students that were absent is; 24

<h3>How to find the Probability?</h3>

Let the total number of students be x .

The number of students which were absent = ¹/₃x.

Number of students which were present = ²/₃x

Thus;

Number of students who attended math's test = ¹/₂x

Number of students who attended physics test = ¹/₄x

No. of students who attended both tests = 6

A denotes number of students who attended math's test

B denotes number of students who attended physics test

Thus;

n(A) = ¹/₂x

n(B) = ¹/₄x

n(A ∩ B) = 6

n(A∪B) = number of students which were present

Thus;

n(A ∪ B) = n(A) + n(B) − n(A∩B)

²/₃x = ¹/₂x + ¹/₄x − 6

²/₃x = ³/₄x - 6

³/₄x - ²/₃x = 6

x = 72

Thus, number of students that were absent = ¹/₃ * 72

Number of students that were absent = 24

Read more about Probability at; brainly.com/question/251701

#SPJ1

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