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Arlecino [84]
4 years ago
15

Find the number of ways to listen to 4 CDs from a selection of 8 CDs.

Mathematics
1 answer:
Sati [7]4 years ago
5 0
1680. 8p4, which is 8!/(8-4)!
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A rectangular garden has a length of 9 feet and a width of 4.5 feet. What is the perimeter of the garden?​
Andreyy89
Answer: 27

Explanation:
P = 2(l+w) = 2 · (9 + 4.5) = 27
6 0
3 years ago
What is the result when 3x3 + 4x2 + 11x + 10 is divided by x + 1?
algol13
The result you get when you divide is 11 + 16/x + 1
3 0
3 years ago
Read 2 more answers
First equation x-y=8<br> second equation x+y=6<br> this would be very helpful
skelet666 [1.2K]
I’m sorry I don’t know
4 0
3 years ago
These data can be approximated quite well by a N(3.4, 3.1) model. Economists become alarmed when productivity decreases. Accordi
CaHeK987 [17]

Answer:

First part

P(X< 3.4-0.6*3.1) = P(X

And for this case we can use the z score formula given by:

z = \frac{x- \mu}{\sigma}

And using this formula we got:

P(X

And we can use the normal standard table or excel and we got:

P(Z

Second part

For the other part of the question we want to find the following probability:

P(-1.715

And using the score we got:

P(-1.715

And we can find this probability with this difference:

P(-1.65< Z< 1.210)=P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the data of a population, and for this case we know the distribution for X is given by:

X \sim N(3.4,3.1)  

Where \mu=3.4 and \sigma=3.1

First part

And for this case we want this probability:

P(X< 3.4-0.6*3.1) = P(X

And for this case we can use the z score formula given by:

z = \frac{x- \mu}{\sigma}

And using this formula we got:

P(X

And we can use the normal standard table or excel and we got:

P(Z

Second part

For the other part of the question we want to find the following probability:

P(-1.715

And using the score we got:

P(-1.715

And we can find this probability with this difference:

P(-1.65< Z< 1.210)=P(Z

8 0
3 years ago
A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5
Elodia [21]

Answer:

7.3% percentage of the bearings produced will not be acceptable.

Step-by-step explanation:

Consider the provided information.

Average diameter of the bearings it produces is .500 inches. A bearing is acceptable if its diameter is within .004 inches of this target value.

Let X is the normal random variable which represents the diameter of bearing.

Thus, 0.500-0.004<X<0.500+0.004

0.496<X<0.504

The bearings have normally distributed diameters with mean value .499 inches and standard deviation .002 inches.

Use the Z score formula: \frac{X-\mu}{\sigma}

Therefore

\frac{0.496-0.499}{0.002}\leq z\leq \frac{0.504-0.499}{0.002}

\frac{-0.003}{0.002}\leq z\leq \frac{0.005}{0.002}

-1.5\leq z\leq 2.5

Now use the standard normal table and determine the probability of that a ball bearing will be acceptable.

P(-1.5\leq z\leq 2.5)=0.9938-0.0668=0.9270

We need to find the percentage of the bearings produced will not be acceptable.

So subtract it from 1 as shown.

1-0.9270=0.073

Hence, 7.3% percentage of the bearings produced will not be acceptable.

3 0
4 years ago
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