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Anna [14]
3 years ago
10

A tire on a toy car has a diameter of 8 cm if the toy car travels 12,560 cm approximately how many times does the tire rotate? U

se 3.14 as an approximation of pi
Mathematics
1 answer:
Marina86 [1]3 years ago
6 0

Answer:

The number of rotations completed by tire  = 500.

Step-by-step explanation:

The diameter of the tire of toy car = 8 cm

Now, DIAMETER = 2 x RADIUS

So, radius of the tire =  D/2  = 8/2 = 4 cm

Now, Circumference of the Circle = 2πr

= 2 x 3.14 x 4 = 25.12 cm

Now, \textrm{Total  number of rotations}  = \frac{\textrm{Total Area covered}}{\textrm{Area covered in 1 rotation}}

= \frac{12,560}{25.12}  = 500

The number of rotations completed by circle = 500.

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How do I find the area of each shape
Ad libitum [116K]

Answer: the formula is (A=bh1/2)


Step-by-step explanation: #4 (The triangle)

First let’s find the base length of the triangle.

28 - 16 = 12

Ok now let’s do the real math now

Area  = bh1/2

Area = (12)(16)(1/2)

Area = 96

Don’t worry about the slant height it’s just there to trick you  




8 0
3 years ago
Someone help with this please
r-ruslan [8.4K]
The Answer is B. I hope this helped.
6 0
3 years ago
Determine what shape is formed for the given coordinates for ABCD, and then find the perimeter and area as an exact value and ro
Helga [31]

Answer:

Part 1) The shape is a trapezoid

Part 2) The perimeter is 25(4+\sqrt{2})\ units   or approximately  135.4\ units

Part 3) The area is 937.5\ units^2

Step-by-step explanation:

step 1

Plot the figure to better understand the problem

we have

A(-28,2),B(-21,-22),C(27,-8),D(-4,9)

using a graphing tool

The shape is a trapezoid

see the attached figure

step 2

Find the perimeter

we know that

The perimeter of the trapezoid is equal to

P=AB+BC+CD+AD

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Find the distance AB

we have

A(-28,2),B(-21,-22)

substitute in the formula

d=\sqrt{(-22-2)^{2}+(-21+28)^{2}}

d=\sqrt{(-24)^{2}+(7)^{2}}

d=\sqrt{625}

d_A_B=25\ units

Find the distance BC

we have

B(-21,-22),C(27,-8)

substitute in the formula

d=\sqrt{(-8+22)^{2}+(27+21)^{2}}

d=\sqrt{(14)^{2}+(48)^{2}}

d=\sqrt{2,500}

d_B_C=50\ units

Find the distance CD

we have

C(27,-8),D(-4,9)

substitute in the formula

d=\sqrt{(9+8)^{2}+(-4-27)^{2}}

d=\sqrt{(17)^{2}+(-31)^{2}}

d=\sqrt{1,250}

d_C_D=25\sqrt{2}\ units

Find the distance AD

we have

A(-28,2),D(-4,9)

substitute in the formula

d=\sqrt{(9-2)^{2}+(-4+28)^{2}}

d=\sqrt{(7)^{2}+(24)^{2}}

d=\sqrt{625}

d_A_D=25\ units

Find the perimeter

P=25+50+25\sqrt{2}+25

P=(100+25\sqrt{2})\ units

simplify

P=25(4+\sqrt{2})\ units ----> exact value

P=135.4\ units

therefore

The perimeter is 25(4+\sqrt{2})\ units   or approximately  135.4\ units

step 3

Find the area

The area of trapezoid is equal to

A=\frac{1}{2}[BC+AD]AB

substitute the given values

A=\frac{1}{2}[50+25]25=937.5\ units^2

4 0
3 years ago
I will give brainliest!
goldfiish [28.3K]

Answer:

Step-by-step explanation:

6 0
2 years ago
Please help i need it
vichka [17]

Answer:

x = 100

Step-by-step explanation:

The area of the left square is 3600

A =s^2

3600 = s^2

Taking the square root of each side

60 =s

The area of the right square is 1600

A =s^2

1600 = s^2

Taking the square root of each side

40 =s

Adding the lengths

60+40 =x

100 =x

3 0
2 years ago
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