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Mademuasel [1]
3 years ago
9

Beth works at a grocery store. She earns $8 per hour for her first 20 hours of work in a week. She earns $11 per hour for workin

g beyond 20 hours. Circle the graph below that shows the relationship between beth’s Earnings and the number of hours she works in a week.
By the way sorry for the confusion with the graph XD but please help

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
3 0

Answer:

the 2nd graph

*this is my first time answering a question xd*

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Approximate the integral integral integral integral f(x, y) dA by dividing the rectangle R with vertices (0, 0), (4, 0), (4, 2),
amm1812

Answer:

Step-by-step explanation:

Approximate the integral \int\int\limits_R {f(x,y)} \, dA by dividing the region R with vertices (0,0),(4,0),(4,2) and (0,2) into eight equal squares.

Find the sum \sum\limits^8_{i=1}f(x_i,y_i)\delta A_i

Since all are equal squares, so \delta A_i=1 for every i

\sum\limits^8_{i=1}f(x_i,y_i)\delta A_i=f(x_1,y_1)\delta A_1+f(x_2,y_2)\delta A_2+f(x_3,y_3)\delta A_3+f(x_4,y_4)\delta A_4+f(x_5,y_5)\delta A_5+f(x_6,y_6)\delta A_6+f(x_7,y_7)\delta A_7+f(x_8,y_8)\delta A_8\\\\=f(0.5,0.5)(1)+f(1.5,0.5)(1)+f(2.5,0.5)(1)+f(3.5,0.5)(1)+f(0.5,1.5)(1)+f(1.5,1.5)(1)+f(2.5,1.5)(1)+f(3.5,1.5)(1)\\\\=0.5+0.5+1.5+0.5+2.5+0.5+3.5+0.5+0.5+1.5+1.5+1.5+2.5+1.5+3.5+1.5\\\\=24

Thus, \sum\limits^8_{i=1}f(x_i,y_i)\delta A_i=24

Evaluating the iterate integral \int\limits^4_0 \int\limits^2_0 {(x+y)} \, dydx=\int\limits^4_0 {[xy+\frac{y^2}{2} ]}\limits^2_0 \, dx =\int\limits^4_0 {[2x+2]}dx\\\\=[x^2+2x]\limits^4_0=24.

Thus, \int\limits^4_0 \int\limits^2_0 {(x+y)} \, dydx=24

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3 years ago
P-6 greater than or equal to 3
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Answer:

p ≥ 9

Step-by-step explanation:

1. Put words into equation

       p-6 greater than or equal to 3 = p-6≥3

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I hope that helped!

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