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4 years ago

If f(x)=3x-2 and g(x)=2x+1, find (f+g)(x)

Mathematics

1 answer:

Nady [450]4 years ago

4 0

Answer:

5x - 1

Step-by-step explanation:

Simply add the binomials together.

(3x - 2) + (2x + 1)

Combine like terms.

[3x + 2x] = 5x

[-2 + 1] = 1

5x + 1

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What is the slope??? Please show step by step!!

aksik [14]

Answer:

In order to find the slope, we would need to format the coordinates like rise over run (y/x)

We find two points, (-6, 12) and (-5, 14)

Now we subtract the y coordinates from each other and do the same for the x coordinates

14 and 12 are our y coordinates so that will be our rise

-5 and -6 are x coordinates so that will be our run

14 - 12 2

_______ = ______

-5 - (-6) 1

2 is the slope

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3 years ago

35 POINT QUESTION, WILL MARK BRAINLIEST. Which of the following options is a 3rd degree polynomial with exactly 1 real root?

Romashka [77]

Answer:

A. F(x) = x^3+9x^2+27x+27

Step-by-step explanation:

I am not 100% sure but I think this is right.

I found the root for this equation: x=-3

Hope this helps!

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3 years ago

Read 2 more answers

Solve: sin2x cosx + cos 2x sin x = √3/2 for 0

artcher [175]

Answer:

$x=\frac{\pi }{9}+\frac{2k\pi }{3} ,\frac{2\pi }{9}+\frac{2k\pi }{3}$

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3 years ago

Sunnys gymnastics class last 1 hour 20 minutes the class starts at 3:50 pm at what time does rhe gymnastics class end

Kisachek [45]

The answer would be 5:10.

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4 years ago

If you know trig please help! Will give brainliest!

kaheart [24]

Answer:

sin^2α

Step-by-step explanation:

I will just pose x instead of alpha here to make things simpler

$\tan ^2\left(x\right)\left(2\cos ^2\left(x\right)+\sin ^2\left(x\right)-1\right)\\\\$

we know that sin^2x = 1 - cos^2x so...

$=\left(-1+1-\cos ^2\left(x\right)+2\cos ^2\left(x\right)\right)\tan ^2\left(x\right)$

$=\cos ^2\left(x\right)\tan ^2\left(x\right)$

we can rewrite using trigonometric identities (tan = sin/cos)...

$=\left(\frac{\sin \left(x\right)}{\cos \left(x\right)}\right)^2\cos ^2\left(x\right)\\= \sin ^2\left(x\right)$

6 0

3 years ago