Answer:
(A) COP = 2.64
(B) rate of heat absorption= 1.9637 kW
Explanation:
mass flow rate (m) = 0.018 kg/s
work input (Win) = 1.2kW
inlet pressure (P1) = 800kPa
inlet temperature (T1) = 35 degree Celsius
h1 = 271.24 KJ/Kg
outlet pressure (P2) = 800 kPa
outlet temperature (T2) = ?
entalphy (h2) = 95.48 KJ/Kg
The entalphies are gotten from tables for refrigerant 134a at the temperatures and pressures above
(A) COP = Qh ÷ Win
where Qh = m(h1 -h2) from the energy balance equation
Qh = 0.018 ( 271.24 - 95.48 ) = 3.1637 kW
COP = 3.1637 ÷ 1.2 = 2.64
(B) rate of heat absorption = Qh - Win
= 3.1637 - 1.2 = 1.9637 kW
The resistance of the circuit is 
Explanation:
We can solve the problem by applying Ohm's law, which gives us the relationship between current, potential difference and resistance in a circuit:

where
V is the potential difference
R is the resistance
I is the current
For the circuit in this problem,
V = 12.6 V
I = 25.4 A
Re-arranging the equation, we can solve for the resistance:

Learn more about current and potential difference here:
brainly.com/question/4438943
brainly.com/question/10597501
brainly.com/question/12246020
#LearnwithBrainly
Answer:
Explanation:
The sum of the pore along the plane is expressed according to Newton's law
Fn-Ff = ma
Fn is the moving force
Ff = nR = frictional force
m is the Mass
a is the acceleration
Substitute the given values
Fn - nR = ma
Fn - tan31°(mgcostheta) =3.9(9.8)
Fn - tan31(3.9(9.8)cos31) = 3.9(9.8)
Fn - tan31(38.22cos31)= 38.22
Fn - 32.76tan31 = 38.22
Fn-19.68 = 38.22
Fn = 38.22+19.68.
Fn = 57.90N
Hence Fn (moving force) of the inclined block is 57.90