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Romashka-Z-Leto [24]
3 years ago
14

wink is the seismic station closest to the earthquake. describe two evidences from the seismogram that demonstrates this?

Physics
1 answer:
kotykmax [81]3 years ago
5 0

Well, we don't know if it's the CLOSEST one, but it's closer than the other ones on this print-out.

There are actually three clues to this in the seismograms:

1). The waves from the tremor reach the Wink station first ... the P wave gets there 50 seconds before Chicago and 3 whole minutes before Tampa.

2). They are stronger (greater amplitude) at Wink than at Chicago or Tampa.

3). The delay between the P wave and the S wave is the smallest at Wink. This delay between the two waves grows as the detector is farther from the quake.

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Why is there more potential for wind energy in the upper himalayan in nepal?​
exis [7]

Answer:

<em><u>The potential area of wind power in the country is about 6074 sq. km with wind power density greater than 300 watt/m2. More than 3,000 MW of electricity could be generated at 5 MW per sq km. The commercially viable wind potential of the country is estimated to be only about 448 MW.</u></em>

5 0
3 years ago
You are loading a refrigerator weighing 2267 N onto a truck, using a wheeled cart. The refrigerator is raised 1.09 m to the truc
meriva

Answer:

a).

Wmin= 2471.03 J

W=1603.01 J

Explanation:

Weight, w= 2267 N

w= m*g\\W=m*g*h \\W=w*h

Minimum work 'h' is the distance the refrigerator is raised h=1.09m

W_{min}=2267 N* 1.09m\\W_{min}=2471.03 J

The motion is no frictional force so, the magnitude of the force with a angle of 45.0° is find using:

W=m*g*h'\\h'= sin(45)\\W=2267N*sin(45)\\W=1603.01 J

6 0
3 years ago
At what rate must a cylindrical spaceship rotate if occupants are to experience simulated gravity of 0.50 gg? Assume the spacesh
Svetradugi [14.3K]

Answer:

The time needed is T  = 16.8 s

Explanation:

From the question we are told that

      The magnitude of the stimulated acceleration due gravity is  a  =  0.5 g

        The diameter of the spaceship is  d =  35m

       

Generally the force acting on the spaceship is  

       F  =  ma

Given that the spaceship is rotating it implies that the force experienced by the occupant is a centripetal force so

      F  = \frac{mv^2}{r}

Thus  

       ma  =  \frac{mv^2}{r}

=>    \frac{v^2}{r}  =  a

      Generally the speed of this spaceship is mathematically represented as

      v =  \frac{2 \pi}{T}

=>    v^2  =   [\frac{2\pi}{T}] ^2

=>     \frac{\frac{4\pi^2 r^2}{T^2} }{r}  = 0.5g

=>       \frac{4 \pi^2 r }{T^2} =  0.5 g

=>         T  = \sqrt{ \frac{4\pi^2 r}{0.5g}}

substituting values

          T  = \sqrt{ \frac{4* (3.142)^2 *(35)}{0.5 * 9.8}}

         T  = 16.8 s

4 0
3 years ago
Read 2 more answers
suppose you want to determine the surface area of this sugar cube. it has edges that are each 2 cm long. if you cut the cube in
ivolga24 [154]

Answer:

Half: 6 cm^2    Whole: 12 cm^2

Explanation:

First, we know that the edges of the cube are 2 cm long. So there are 6 faces on a cube. We do 2x6=12 cm^2 as our total surface area. Then it asks for each half. So you would divide it by 2 and get 6 cm^2 as your half.

5 0
3 years ago
A skateboarder is standing at the top of a tall ramp waiting to begin a trip. The skateboarder has
Mnenie [13.5K]
Has a skateboard. your gonna have to give more details the. that just one .
7 0
3 years ago
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