Answer:
1000 m/s
Explanation:
Given that
Mass of the ball, m = 10 g = 0.01 kg
Charge of the ball, q = 2 C
Field strength of the field, E = 5 N/C
Acceleration of the ball, a = ? m/s²
We know the the equation holds,
F = qE, on substituting, we have
F = 2 C * 5 N/C
F = 10 N
Also, we know that
F = ma, and as such,
a = F / m, on substituting we have
a = 10 N / 0.01 kg
a = 1000 m/s²
Therefore, the acceleration of the ball is 1000 m/s²
For an ideal case the temperature should be zero.
That would be a decomposer
Hope this helps!
The answer is D. If you aren't consistent with your drop positions, then your data may be invalid. To be frank: it basically screws over the experiment.
Answer:
Explanation:
What we are basically looking for here is how long it takes the first stone to hit the water. We have everything we need to figure that out. We will use the equation
Δx = . Filling in, we will solve for t, the time is takes the first stone to hit the water (which is the same for both since they both hit the water at the same time):
which is a quadratic that we will have to factor. Get it into standard form, setting it equal to 0:
and factor to get that
t = 3.2 s and t = -2.8 s
Since time can't ever be negative, it takes 3.2 s for the stones to hit the water.