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Juli2301 [7.4K]
3 years ago
7

Why is the time needed to vaporize the sample of water significantly greater than the time needed to melt the sample? A)Signific

antly more energy is needed to lower the kinetic energy of the molecules. B)Significantly more energy is needed because ice has a lower kinetic energy than liquid water. C)Significantly more energy is required since water vapor (steam) is so much hotter than liquid water. D)Significantly more energy is required to vaporize water because the intermolecular forces between molecules are being completely broken.
Physics
1 answer:
photoshop1234 [79]3 years ago
6 0

Answer:

D) Significantly more energy is required to vaporize water because the intermolecular forces between molecules are being completely broken.

Explanation:

Different states of matter differ because of intermolecular distance between them . Molecules are closest in solid state and farthest in gaseous state . To separate them energy is needed . When matter changes state from liquid to gas , the distance between the molecule increases enormously . Hence energy requirement too is large . When matter changes state from solid to liquid , their mutual separation does not increase much so energy requirement too is lesser. Moreover there is tremendous increase in their volume in gaseous state due to which gas has to do work against external pressure which requires much energy.

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A rocket explodes into two fragments, one 25 times heavier than the other. The magnitude of the momentum change of the lighter f
V125BC [204]

Answer:

B) The same as the momentum change of the heavier fragment.

Explanation:

Since the initial momentum of the system is zero, we have

0 = p + p' where p = momentum of lighter fragment = mv where m = mass of lighter fragment, v = velocity of lighter fragment, and p' = momentum of heavier fragment = m'v' where m = mass of heavier fragment = 25m and v = velocity of heavier fragment.

0 = p + p'

p = -p'

Since the initial momentum of each fragment is zero, the momentum change of lighter fragment Δp = final momentum - initial momentum = p - 0  = p

The momentum change of heavier fragment Δp' = final momentum - initial momentum = p' - 0 = p' - 0 = p'

Since p = -p' and Δp = p and Δp' = -p = p ⇒ Δp = Δp'

<u>So, the magnitude of the momentum change of the lighter fragment is the same as that of the heavier fragment.  </u>

So, option B is the answer

4 0
3 years ago
A 2.0-kg silverware drawer does not slide readily. The owner gradually pulls with more and more force, and when the applied forc
topjm [15]

Answer: 0.45

Explanation:

First note that the body that causes the body to move is its moving force (Fm) which is 9.0N

Since the mass of the body is 2.0kg, the weight will be;

W= mg = 2×10

W= 20N

For static body, the frictional force (Ff) acting on the body is equal to the moving force (Fm) since both forces acts along the horizontal on the body.

Ff = Fm = 9.0N

The normal reaction (R) on the body will also be equal to its weight(W) since weight acts downwards and the reaction acts in the opposite direction (upwards).

R = W = 20N

Ff = nR taking 'n' as coefficient of static friction between the drawer and the cabinet.

9.0 = 20n

n = 9/20

n = 0.45

7 0
3 years ago
incline plane is given length 12m,load 600 newton,effort 200 Newton, Height 3 metre find its velocity ratio and mechanical advan
Salsk061 [2.6K]

Answer:

i. The velocity ratio of the plane is 4.

ii. The mechanical advantage of the plane is 3.

Explanation:

i. The velocity ratio (VR) of an inclined plane is ratio of its length to the height. It is given as;

VR = \frac{length of the plane}{height} = \frac{l}{h}

Given: l = 12 m, L = 600 N, E = 200 N, h = 3 m.

So that,

VR = \frac{12}{3}

     = 4

The velocity ratio of the plane is 4.

ii. Mechanical advantage (MA) expresses the relationship between the load overcome to effort applied.

MA = \frac{Load}{Effort} = \frac{L}{E}

      = \frac{600}{200}

      = 3

The mechanical advantage of the plane is 3.

Therefore, the velocity ratio of the inclined plane is 4, and its mechanical advantage is 3.

7 0
3 years ago
At what height above the ground must a mass of 10 kg be to have a potential energy equal in value to the kinetic energy possesse
Paladinen [302]

Answer:

20 m

Explanation:

We'll begin by calculating the kinetic energy of the mass. This can be obtained as follow:

Mass (m) = 10 kg

Velocity (v) = 20 m/s

Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 10 × 20²

KE = 5 × 400

KE = 2000 J

Finally, we shall the height to which the mass must be located in order to have potential energy that is the same as the kinetic energy. This can be obtained as follow:

Mass (m) = 10 kg

Acceleration due to gravity (g) = 10 m/s²

Potential energy (PE) = Kinetic energy (KE) = 2000 J

Height (h) =..?

PE = mgh

2000 = 10 × 10 × h

2000 = 100 × h

Divide both side by 100

h = 2000 / 100

h = 20 m

Thus, the object must be located at a height of 20 m in order to have potential energy that is the same as the kinetic energy.

5 0
3 years ago
One gram of pure gold would contain lots of gold
Agata [3.3K]

Answer:

One gram of pure gold would contain lots of gold atoms- A.

3 0
3 years ago
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