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Nadya [2.5K]
3 years ago
7

At what height above the ground must a mass of 10 kg be to have a potential energy equal in value to the kinetic energy possesse

d by a mass of 10 kg moving with a velocity of 20 m/s? 100 m 10 m 50 m 20 m
Physics
1 answer:
Paladinen [302]3 years ago
5 0

Answer:

20 m

Explanation:

We'll begin by calculating the kinetic energy of the mass. This can be obtained as follow:

Mass (m) = 10 kg

Velocity (v) = 20 m/s

Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 10 × 20²

KE = 5 × 400

KE = 2000 J

Finally, we shall the height to which the mass must be located in order to have potential energy that is the same as the kinetic energy. This can be obtained as follow:

Mass (m) = 10 kg

Acceleration due to gravity (g) = 10 m/s²

Potential energy (PE) = Kinetic energy (KE) = 2000 J

Height (h) =..?

PE = mgh

2000 = 10 × 10 × h

2000 = 100 × h

Divide both side by 100

h = 2000 / 100

h = 20 m

Thus, the object must be located at a height of 20 m in order to have potential energy that is the same as the kinetic energy.

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Answer:

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Explanation:

Part (a)

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Part (b)

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Thus the voltage across the trimmer is:

V_{T}=IR_{T}\\V_{T}=(6.4)*(17.9)\\V_{T}=114.44V

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Answer:

Height will be 3.8971 m        

Explanation:

We have given that radius of the solid r = 1.60 m

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Transnational Kinetic energy is given by KE=\frac{1}{2}mv^2 as we know that v = v=\omega r

So KE=\frac{1}{2}m(\omega r)^2

Rotational kinetic energy is given by KE_{ROTATIONAL}=\frac{1}{2}I\omega ^2=\frac{1}{2}\left ( \frac{1}{2}mr^2 \right )\omega ^2=\frac{1}{4}m(r\omega )^2

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According to energy conservation

mgh=\frac{1}{2}m(\omega r)^2+\frac{1}{4}m(\omega r)^2

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Vas happenin!
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Answer:

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