All categories

4 years ago

An accountant earned $1109 a week last year. What was her yearly salary?

Mathematics

1 answer:

Effectus [21]4 years ago

7 0

Hello!

<h2>Answer:</h2>

The accountant's yearly salary is $57,668.00.

<h2>___________________________________</h2><h2>Explanation:</h2>

We know that she earns $1,109 per week.

There are about 52 weeks in a year.

$1,109 × 52 = 57,668

You might be interested in

What is the value of X ?

Katyanochek1 [597]

Answer:

X=84

Step-by-step explanation:

180(the sum of the interior triangle angles) - [(180-130)+(180-134)]

6 0

4 years ago

when a number is added to 1/5 of itself, the result is 24. the equation that models this problem is n 1/5 n = 24. what is the va

GuDViN [60]

Let n be unknown number, then 1/5 of this number is 1/5n. When you add these two numbers, you get

$n+\dfrac{1}{5} n.$

You know that this sum is equal to 24, so

$n+\dfrac{1}{5} n=24.$

1. Multiply this equation by 5:

$5n+n=120.$

2. Solve it:

$6n=120,\\n=120:6,\\n=20.$

Answer: n=20, correct choice is B.

4 0

3 years ago

Read 2 more answers

True or false - A risk ratio and an odds ratio are different names for the same concept

aalyn [17]

True would be right

6 0

2 years ago

What is the square root of 3,600

Ira Lisetskai [31]

The answer is 60. think of it like this. the square root of 36 is six and 2 zeros halved is 1 zero so yes, it's 60

8 0

3 years ago

Read 2 more answers

Need help simplifying this

diamong [38]

The simplified answer is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$ .

<u>Step-by-step explanation:</u>

$$\frac{3 y+2 x}{z+2 x}-\frac{2 y-3 x}{3 x+y}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

To add or subtract denominators of the fraction must be same.

If it is not the same, we must take LCM of the denominators. and so we can add the fractions.

To make the denominator same multiply the 1st term $(\frac{3x+y}{3x+y})$ and 2nd term by $(\frac{z+2x}{z+2x})$

= $\frac{(3 y+2 x)(3 x+y)}{(z+2 x)(3 x+y)}-\frac{(2 y-3 x)(z+2 x)}{(3 x+y)(z+2 x)}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

LCM of the denominators is 6x²+ 3xz + 2xy +yz.

Multiply the factors in the numerator.

= $\frac{\left(6 x^{2}+3 y^{2}+11 x y\right)}{(z+2 x)(3 x+y)}-\frac{\left(2 y z+4 x y-3 x z-6 x^{2}\right)}{(3 x+y)(z+2 x)}-\frac{2 z y+6 x z}{6 x^{2}+3 x z+2 x y+y z}$

Now, the denominators are same, you can subtract it.

= $\frac{\left(6 x^{2}+6 x^{2}+11 x y-4 x y-2 y z-2 y z+3 x z-6 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

= $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

Thus the simplified solution is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

4 0

4 years ago