Let AM be the distance between point A and the right wall and AN be the distance between A and the left wall.
Δ AMB is an isosceles right triangle and Δ ANC is half of an equilateral triangle.
Length of AM = 30 m. Length of AN = 1/2 · 80 = 40 m.
The distance between the walls is:
30 m + 40 m = 70 m.
Answer: D
Step-by-step explanation:
Answer:
see below
Step-by-step explanation:
This would be true if the lines are parallel. We have no information about the lines, so we cannot assume the lines are parallel, so we cannot use the corresponding angles theorem
Answer:
10/16
Step-by-step explanation:
Find the common factor between both
5/8 = 10/16
10/16 > 3/16
Using the image I gave you, you don't need to solve for x.
So tan is opposite/adjacent
sin: opposite/hypotenuse
cos: adjacent/hypotenuse
Take theta and do: adjacent/hypotenuse which is cosine
cos theta = adjacent/hypotenuse
cos theta = 1.5/9
inverse cos = 1.5/9 and the answer is: 80.4 degrees