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Anettt [7]
4 years ago
13

If f(x) = 2х2 + 3 and g(x) = х2 -7, find (f- а)(x).

Mathematics
1 answer:
Lerok [7]4 years ago
7 0

Answer:

C. x^2 -4

Step-by-step explanation:

What you do is subtract the functions as said by

(f-g)(x).

so:

f(x)-g(x)

(2x^2+3) - (x^2 -7)

2x^2 -x^2 +3 - 7= x^2 -4

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A square field has an area of 10 square miles. What is the approximate length, to the nearest thousandth, of one side of this fi
Mice21 [21]

Answer: A

Step-by-step explanation: square has 4 sides 10/4=2.5

4 0
3 years ago
2. You are creating a cone-shaped hat for a kid’s costume. You measure the circumference of the child’s head and find it to be 2
Monica [59]
Just draw a triangle(front view) and the slant/inclined sides of it are known to be 8 and you found out radius as 3.26. so mark the diameter by doubling radius.

so the material required would be a slice(like pizza slice) of a circle of radius= 8 and arc length = circumference given ,that is 20.5

now using this find the area of sector/slice. its the answer to the last bit.

now coming to next question, go to the kitchen and take any can and measure its dia and height by using a scale. and you might already know the formula to find the suface area of cylinder.
3 0
3 years ago
Help me please assap
Reil [10]

Answer:  G

<u>Step-by-step explanation:</u>

(x, y) → (\frac{1}{8}x, \frac{1}{8}y)

means that the new quadrilateral will be \frac{1}{8} the size of the original quadrilateral, so it will be smaller because the it maps to a fraction that is less than 1.

5 0
3 years ago
A ship leaves port on a bearing of 34.0 and travels 10.4 mi. the ship then turns due east and travels 4.6mi. how far is the ship
Natasha2012 [34]
A bearing of 34° corresponds to corresponding angle of θ=90-34=56°
The (x,y) values for the position of the ship after completing its first heading are:
x=(10.4cos 56)
y=(10.4sin56)

The trigonometric angle for θ=90-90=0
The (x,y) values for the postion of the ship after completing the second bearing is:
x=(10.4 cos56)+(4.6cos0)≈10.4 mi
y=(10.4sin56)+(4.6sin0)≈8.6mi

the distance from the port will therefore be:
d=√(10.4²+8.6²)≈13.5 miles

It trigonometric angles is:
θ=arctan(y/x)
θ=arctan(8.6/10.4)
θ≈39.6°
Thus the bearing angle is:
90-39.6=50.4°
6 0
3 years ago
Help please I need help
serg [7]
He could use the mode of 89.
6 0
4 years ago
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