<span>Traveled Downstream a distance of 33 Mi and then came right back. If the speed of the current was 12 mph and the total trip took 3 hours and 40 minutes.
Let S = boat speed in still water then (s + 12) = downstream speed (s -12) = upstream speed
Given Time = 3 hours 40 minutes = 220 minutes = (220/60) h = (11/3) h Time = Distance/Speed
33/(s +12) + 33/(s-12) = 11/3 3{33(s-12) + 33(s +12)} = 11(s+12) (s -12) 99(s -12 + s + 12) = 11(</span> s^{2} + 12 s -12 s -144) 99(2 s) = 11(s^{2} -144) 198 s/11 = (s^{2} -144) 18 s = (s^{2} -144) (s^{2} - 18 s - 144) = 0 s^{2} - 24 s + 6 s -144 =0 s(s- 24) + 6(s -24) =0 (s -24) (s + 6) = 0 s -24 = 0, s + 6 =0 s = 24, s = -6 Answer) s = 24 mph is the average speed of the boat relative to the water.
Answer:
Really
Step-by-step explanation:
Let's set up two equations:
x+y=20 We know she brought total of 20, some of each so x=small y=big
20x+ 30y=450
x+y= 20
-y -y
------------
x= 20 -y
substitute into the other equation:
20 (20-y) + 30y = 450
400 - 20y + 30y = 450
400+ 10 y = 450
10 y = 50
y= 5
So she brought 5 big cases. Then substitute the value of y into one of the equations.
5+ x = 20
x= 15
So we bought 15 small cases and 5 big cases.
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The final probability is the weighted average of the playing probabilities calculated over the possible weather options:
P(john practices cello; given that it rains) * P(it rains) +
P(john practices cello; given that it does not rain) * P(it does not rain) =
0.6 * 0.7 + 0.4 * 0.3 = 0.54
The probability is 54%
