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Katarina [22]
3 years ago
11

Please answer quick, thank you for your time.

Mathematics
2 answers:
Vinil7 [7]3 years ago
8 0

Answer:

7 1/2

7 5/12

4 14/15  

6 5/6

Step-by-step explanation:

lara31 [8.8K]3 years ago
5 0

Answer:

7 1/2

7 5/12

4 14/15  

6 5/6

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Helpppppp meeeeeeeee​
seropon [69]

Answer:

its B im pretty sure.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the flux of F=(x^5+y^5+z^5-2x-3y-4z)i+sin(2y)j+4zsin^2(y)k across the surface of the tetrahedron bounded by the coordinate
Tju [1.3M]
Use the divergence theorem.

\mathbf F(x,y,z)=(x^5+y^5+z^5-2x-3y-4z)\,\mathbf i+\sin2y\,\mathbf j+4z\sin^2y\,\mathbf k
\implies(\nabla\cdot\mathbf F)(x,y,z)=\dfrac{\partial(x^5+y^5+z^5-2x-3y-4z)}{\partial x}+\dfrac{\partial(\sin2y)}{\partial y}+\dfrac{\partial(4z\sin^2y)}{\partial z}=5x^4-2+2\cos2y+4\sin^2y

The flux of \mathbf F across the tetrahedron's surface S is then given by the integral of \nabla\cdot\mathbf F over the interior of the tetrahedron \mathbf R.

\displaystyle\iint_S\mathbf F\cdot\mathrm dS=\iiint_T\nabla\cdot\mathbf F\,\mathrm dV
=\displaystyle\int_{x=0}^{x=1}\int_{y=0}^{y=1-x}\int_{z=0}^{z=1-x-y}(5x^4-2+2\cos2y+4\sin^2y)\,\mathrm dz\,\mathrm dy\,\mathrm dx
=\dfrac1{42}
4 0
3 years ago
Cole ate 2/3 of the cookies in the cookie jar. Jim ate 1/4 of the cookies
djyliett [7]

Answer:

6

Step-by-step explanation:

first, we start with 2 dozen = 2 * 12 = 24 cookies

next, cole eats 2/3 of the cookies

2/3 of the cookies = 2/3 * 24 = 16

we are then left with

original # - # of cookies cole ate = 24 - 16 = 8

next, jim eats 1/4 of the cookies left

cookies left = 8

1/4 of cookies left = 1/4 * 8 = 2

cookies left - cookies jim eats = cookies still in jar = 8 - 2 = 6

3 0
2 years ago
Please help me with 21 and 22! Thank you.
Artyom0805 [142]
#21

To find the area of rectangle, you multiple length by width, so that would be (\ \sqrt{2x}\ )(\ \sqrt{6x}\ ) = \sqrt{2x\cdot6x} = \sqrt{12x^2} = x\sqrt{4\cdot3} = \boxed{2x\sqrt3}

Since we are talking about area \ length, x need to be positive so we don't need to worry about absolute value now.

#22

The area of triangle is \dfrac12bh, so that would be
\dfrac12\sqrt{18y}\cdot\sqrt{2y^4}\\\ \\=\dfrac{y^2}2\sqrt{18y}\cdot\sqrt{2}\\\ \\=\dfrac{y^2}2\sqrt{18y\cdot2}\\\ \\=\dfrac{y^2}2\sqrt{36y}\\\ \\=\dfrac{y^2}2\sqrt{4\cdot9\cdot y}\\\ \\=\boxed{3y^2\sqrt y}\text{ or }\boxed{3\sqrt{y^5}}

Hope this helps.
7 0
3 years ago
Can someone pls help me!!
stich3 [128]

Answer:

The mice could not hide from predators.

Step-by-step explanation:

The mouse is white , where as the vegetation around it is brown.

6 0
4 years ago
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