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3 years ago

Please answer quick, thank you for your time.

Mathematics

2 answers:

Vinil7 [7]3 years ago

8 0

Answer:

7 1/2

7 5/12

4 14/15

6 5/6

Step-by-step explanation:

lara31 [8.8K]3 years ago

5 0

Answer:

7 1/2

7 5/12

4 14/15

6 5/6

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Is the expression 70 – (4 • 15) a difference of three terms, a product of two terms, or a difference of two terms?

nlexa [21]

Answer:

7 4 and 15 because term means numbers

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2 years ago

Evaluate the function for the given value. f(-3) if f(x) = 4x 2 + 7x

Natasha_Volkova [10]

Answer:

x = 15

Step-by-step explanation:

f(x) = 4x² + 7x

= 4(-3)² + 7(-3)

= 36 + (-21)

= 15

3 0

3 years ago

Please please please help and solve this with steps, much help needed thank you :) 20 points for this!

leonid [27]

Answer:

$y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}$

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

$\frac{dy}{dx}y=x^3+2x-5x+3$

$\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}$

$\mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)$

1. $\mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:$

$y'\:y=x^3+2x-5x+3$

2. $\mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}$

$yy'\:=x^3-3x+3$

$N\left(y\right)\cdot y'\:=M\left(x\right)$

$N\left(y\right)=y,\:\quad M\left(x\right)=x^3-3x+3$

3. $\mathrm{Solve\:}\:yy'\:=x^3-3x+3:\quad \frac{y^2}{2}=\frac{x^4}{4}-\frac{3x^2}{2}+3x+c_1$

4. $\mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}$

5. $\mathrm{Simplify}$

$y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}$

7 0

3 years ago

Read 2 more answers

Simplify the expression. 13[6^2/(5^2-4^2)+9] 181 169 26 585

Zina [86]

So 5^2 -4^2 is 25-16 which is 9
6^2/9 is 36/9 which is 4 +9 is 13
13(13) is 169

7 0

3 years ago

Cos15°°- Sin 15°= 1/√2

ololo11 [35]

<h2>Refer this attachment</h2>

Hope it's help you

4 0

3 years ago