Question

Listed below are body temperatures from five different subjects measured at 8 AM and again at 12 AM.

Answer 1

Answer:

The value of $\bar d$ is -0.2.

The value of $s_{\bar d}$ is 0.3464.

$\mu_{d}$ = mean difference in body temperatures.

Step-by-step explanation:

The data for body temperatures from five different subjects measured at 8 AM and again at 12 AM are provided.

The formula of $\bar d$ and $s_{\bar d}$ are:

$\bar d=\frac{1}{n}\sum (x_{1}-x_{2})$

$s_{\bar d}=\sqrt{\frac{1}{n-1}\sum (d_{i}-\bar d)^{2}}$

Consider the table below.

Compute the value of $\bar d$ as follows:

$\bar d=\frac{1}{n}\sum (x_{1}-x_{2})=\frac{1}{5}\times-1=-0.2$

Thus, the value of $\bar d$ is -0.2.

Compute the value of $s_{\bar d}$ as follows:

$s_{\bar d}=\sqrt{\frac{1}{n-1}\sum (d_{i}-\bar d)^{2}}=\sqrt{\frac{0.48}{4}}=0.3464$

Thus, the value of $s_{\bar d}$ is 0.3464.

The variable $\mu_{d}$ represents the mean difference in body temperatures  measured at 8 AM and again at 12 AM.