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andrew11 [14]
2 years ago
8

Given that у=6 cm and θ=15 °, work out x rounded to 1 decimal place.

Mathematics
2 answers:
Lubov Fominskaja [6]2 years ago
7 0
Sin(15)=6/x
x=6/sin(15)
x=23.2°
mart [117]2 years ago
6 0

Answer:

1.6

Step-by-step explanation:

it said it was on hegarty

:)

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A model of a car uses a scale of 2 1/4 inches = 3 feet. If the model is 14 inches long, what is the actual length of the car?
MatroZZZ [7]

Answer:

36" / 2.25"  * 14 = 16 * 14" = 224 inches =

18.666666 feet = 18 feet 8 inches

Step-by-step explanation:

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3 years ago
The population of a city is 218720.
vodka [1.7K]
Correct Answer is 205,857
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How to do improper fractions with 3.8 repeating
vivado [14]
3.88888=3.88888/1=38.8888888

so lets ssay our repeating decimal = a fraction x
x=3.888 is true
multiply by 10
10x=38.8888
now subtract fir frist eqation from second
10x-x=38.8888-3.888888
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3 0
3 years ago
The sum of three numbers is 24. the largest number is three times the smallest, and the middle number is four less than the larg
tensa zangetsu [6.8K]
Small number =X
mid number = 3X-4
large number = 3x

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6 0
3 years ago
Compute the exact interest on $5,870 at 12% if the money is borrowed from June to December of the same year.
yawa3891 [41]

Answer:

The exact interest on $5,870 at 12% is $410.9

Step-by-step explanation:

From the information provided we know that

Principal amount: $5,870

Interest rate: 12% -> 0.12

Time: 7 months (From June to December)

When you know the principal amount, the rate, and the time, the amount of interest can be calculated by using the formula:

I=P\cdot r\cdot t

where P is principal, r is the rate of interest and t is the time in years.

We need to convert the 7 months into 1 year.

7 \>months \cdot \frac{1 year}{12 months} = \frac{7}{12} year

Now we can use the above formula

I=P\cdot r\cdot t=5870\cdot 0.12 \cdot \frac{7}{12} \\I = 0.12\cdot \frac{7\cdot \:5870}{12}\\I = 0.12\cdot \frac{20545}{6}\\I = \frac{2465.4}{6}\\I = 410.9

Therefore the exact interest on $5,870 at 12% is $410.9

7 0
3 years ago
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