The given sequence is
a₁ = 29
a₂ = 39
a₃ = 49
a₄ = 59
This sequence is an arithmetic sequence. Th first term is a₁ = 29, and the common difference is d= 10.
The n-th term is

The 33-rd termis
a₃₃ = 29 + (33 - 1)*10
= 29 + 320
= 349
Answer: a₃₃ = 349
Answer:
6ml
Step-by-step explanation:
=25%÷100%
=0•25
1.5l to ml
1L=1000ml
=1.5000ml÷0.25
=6ml
Hello,
Let's f the age of the father
s the age of Simran
f=3*s
f-5=4*(s-5)
==>3s-5=4s-20
==>s=15
f=3*15=45
Answer:d
Step-by-step explanation: