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fredd [130]
3 years ago
9

A recovering heart attack patient is told to get on a regular walking program. The patient is told to walk a distance of 5 km th

e first week, 8 km the second week, 11 km the third week and so on for a period of 10 weeks. At that point the patient is to maintain the distance walked during the 10th week. How far will the patient walk during the 10th week? a. Is the sequence arithmetic or geometric? Explain your answer.
Mathematics
1 answer:
lesya [120]3 years ago
4 0
He is to maintain waling 31km a week 
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Jorge has 10 apples and Stacy takes away 3 apples. How many apples does Jorge has less than Stacy?
marin [14]

Answer: 7

Step-by-step explanation:

5 0
3 years ago
Micheal buys a basket of mangoes on sale for 4 dollars before tax. The sales tax is 12%. What is the total price Micheal pays fo
nikitadnepr [17]

Answer:

$4.48 <em>is the total price.</em>

Step-by-step explanation:

<em>Mulitply the total by the percentage.</em>

<em />

4 * .12 = .48

<em>Add those together. </em>

<em />

4 + .48 = 4.48

<em>Total price of mangoes: $</em>4.48<em> </em>

6 0
3 years ago
find the volume of cubical box . if the cost of painting of outer surface is rs 1440 at the rate rs 15 per mcube
bearhunter [10]
Surface of a cubical box=6(side²)

1)We have to calculate the surface of this cubical box.
Rate=cost of painting / surface  ⇒surface=cost of painting/rate

Data:
Rate=$15/m²
cost of painting=$1440

Surface=$1440/($15/m²)=96 m²

2)We find out the length of the side:

Surface of a cubical box=6(side²)

Data:
Surface of a cubical box=96 m2

Therefore:
96m²=6 (side²)
side²=96 m²/6
side²=16 m²
side=√(16 m²)=4 m

3) We find the volume of a cubical box.
volume=(side³)
volume=(4 m)³
volume=64 m³

Answer: the volume of this cubical box would be 64 m³.

3 0
3 years ago
Write an algebraic expression that Marshall can use to determine the total cost of buying a watermelon that weighs w pounds and
VMariaS [17]

Answer:

The answer is that the cost will be a total of: $142.05. That is $125.80 for Watermelon that weighs 185 lbs and $16.25 for 5 lbs of tomatoes.

Step-by-step explanation:

Given: Watermelons are .68 / lb and tomatoes are 3.25 / lb.

Let w = watermelon weight and tomato weight.

An equation would be:

.68w + 3.25t = Total cost

For 185 lb of Watermelon and 5 lbs of tomatoes:

.68(185) + 3.25(5) =

$125.80 + $16.25 = $142.05

3 0
3 years ago
A single card is drawn from a standard 52-card deck. Let D be the event that the card drawn is a black card and let F be the eve
tester [92]

Answer:

The indicated probability of P(D \cup F')=\frac{25}{26}

Step-by-step explanation:

Probability of an event E to be;

P(E) = \frac{Number of events within E}{Total number of possible outcomes}

As per the given condition:

Total number of possible outcomes =  52 cards.

Let the event be D and F as follows;

D : Drawn card is a black card

F : Drawn card is a 10 card.    

Then,

From the given condition:

P(D) = \frac{26}{52}   [Out of 52 cards, 26 were black] ,

P(F) = \frac{4}{52}    [Out of 52 cards, there are four  10 cards]

For any two events A and B we always have;

P(A \cup B) = P(A)+P(B)-P(A \cap B)

Now, we have to find the indicated probability:

P(D \cup F')=P(D)+P(F')-P(D \cap F')               ......[1]

First find the P(F');

P(F') =1-P(F) = 1-\frac{4}{52} =\frac{52-4}{52} =\frac{48}{52}

Also, to find P(D \cap F').

We use the formula :

For any event A and B independent variable.

P(A \cap B) =P(A) \cdot P(B)

then;

P(D \cap F') =P(D) \cdot P(F') = \frac{26}{52} \cdot \frac{48}{52} =\frac{24}{52}

Now, substitute these in [1];

P(D \cup F')=\frac{26}{52} +\frac{48}{52} -\frac{24}{52}=\frac{26+48-24}{52} =\frac{50}{52} = \frac{25}{26}

Therefore, the probability of P(D \cup F')=\frac{25}{26}



3 0
3 years ago
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