Answer:
Explanation:
As a user of GPL v3 software, you have lots of freedom: You can use GPL software for commercial purposes. You can modify the software and create derivative work. You can distribute the software and any derivative work you produce, without having to ask for permission or pay
Answer:
Option B and Option D
are correct answers.
Explanation:
To view the invoice data on the related account records in sales force when invoices are stored in SAP we must:
- Create an External Object connected to an invoice table in SAP
OR
- Connect to an O-Data Publisher Service for SAP databases.
SAP can be defined as Systems, Applications and Products. SAP is basically a software which has a backbone of SAP ERP (most advance Enterprise Resource Planing). SAP software helps to manage many business areas by providing powerful tools that include financial and logistic areas.
<h2 /><h2>I hope it will help you!</h2>
Answer:
Base name or -b command is used to locate only match directory in Linux.
Explanation:
base name can primarily be used in shell script.
As we know that base name can be described as a standard UNIX computer program. When we give a path name to any base then it deletes each and every prefix up to the last slash character and give back the result. base name can be defined in the Single UNIX Specification
Answer:
bootrec/rebuildbcd
Explanation:
Several reason could have caused this, ranging from failed updates or installations to boot sector virsues etc
To fix this, you will need to restart the computer (Alt+Ctrl+Del) into recovery mode, Write the bootrec/rebuildbcd command and press enter or bootrec/fixboot.
If the task is successful, you will get a message "The operation completed successfully."
Then you are free restart your computer
Answer:
The program to this question can be describes as follows:
Program:
#include <stdio.h> //defining header file
int main() //defining main method
{
int n,i,x=0; //defining integer variable
printf("Enter a number: "); //print message
scanf("%d",&n); //input value from the user
printf("%d\n",n); //print input value
for(i=1;i<n;i++) //loop to count reverse number
{
x=n-i; //calculate value
printf("%d\n",x); //print value
}
return 0;
}
Output:
Enter a number: 3
3
2
1
Explanation:
- In the above program, three integer variable "n,i and x" is declared, in which variable n we take input from the user end and the variable i and x is used in the loop to calculate the value in the reverse order.
- In the next step, a loop is declared, in which the variable x calculates the value in reverse order and uses a print method to print its value.
