Explanation:
The given data is as follows.
Flow of chlorine (Q) = 
Amount of liter present per day is as follows.

It is given that dosage of chlorine will be as follows.
10 mg/l =
kg/l
Therefore, total chlorine requirement is as follows.
Total chlorine requirement =
kg/day
= 100 kg/day
Thus, we can conclude that the kilograms of chlorine used daily at the given water treatment plant is 100 kg/day.
Answer:Increased the number of molecular collisions and increased the reaction rate
Explanation:
Answer:
Following are the solution to this question:
Explanation:
If the draw a line perpendicular with y-axis thru the diagonal line check but it meets only one curved point, therefore the curve indicates a function not otherwise. They draw a vertical line perpendicular to the y-axis there, it just intersects one more chart point, which is why a graph is a feature:
In point a:
In point b:
Its y-axis length cut also by understanding the benefits of y-interception and the x-axis length gives the x-intercept.

In point C:
Every graph is y-axis symmetric because the left side of the column as well as the middle side of the graph is about the same.
Answer:
A. 2Fe + 3Cl2 --> 2FeCl3
B. 2Fe + 3O2 --> 2Fe2O3
C. C4H10O + 4O2 --> 4CO2 + 5H2O
D. C7H16 + 11O2 --> 7CO2 + 8H2O
Explanation:
Answer:
0.067 M
Explanation:
Given data:
Volume of solution = 1.00 L
Mass of BaCl₂ = 14 g
Molarity of solution = ?
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Now we will calculate the number of moles first.
Number of moles = mass/ molar mass
Number of moles = 14 g/ 208.23 g/mol
Number of moles = 0.067 mol
Now we will calculate the molarity.
Molarity = 0.067 mol / 1.00 L
Molarity = 0.067 M ( mol/L=M)