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Lilit [14]
3 years ago
9

The mass of a watch glass was measured four times. The masses were

Chemistry
2 answers:
kenny6666 [7]3 years ago
5 0

Answer:

\large \boxed{\text{100.005 g}}

Explanation:

\text{Average mass} = \dfrac{\text{Sum of all measurements}}{\text{Number of measurements}}

1. Sum of Measurements

\begin{array}{cr}\textbf{No.}& \textbf{Mass/g} \\1& 99.997 \\2& 100.008 \\3& 100.011 \\4& 100.005 \\\text{Sum } = & \mathbf{400.021}\\\end{array}

2. Average mass

\text{Average mass} = \dfrac{\text{400.021 g}}{4} = \textbf{100.005 g}\\\\\text{The average mass of the watch glass is $\large \boxed{\textbf{100.005 g}}$}

tigry1 [53]3 years ago
4 0
To get the mass of the glass watch. It’s very simple. Take all 4 numbers 99.997, 100.008, 100.011, 100.005 add them together and then divide them by 4 bc there were 4 numbers to begin with.
The mass of the glass is- 100.00525 g
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Consider the following reaction: CO(g)+2H2(g)⇌CH3OH(g) Kp=2.26×104 at 25 ∘C. Calculate ΔGrxn for the reaction at 25 ∘C under eac
valentinak56 [21]

Answer : The value of \Delta G_{rxn} is, 8.867kJ/mole

Explanation :

The formula used for \Delta G_{rxn} is:

\Delta G_{rxn}=\Delta G^o+RT\ln Q   ............(1)

where,

\Delta G_{rxn} = Gibbs free energy for the reaction

\Delta G_^o =  standard Gibbs free energy

R = gas constant = 8.314 J/mole.K

T = temperature = 25^oC=273+25=298K

Q = reaction quotient

First we have to calculate the \Delta G_^o.

Formula used :

\Delta G^o=-RT\times \ln K_p

Now put all the given values in this formula, we get:

\Delta G^o=-(8.314J/mole.K)\times (298K)\times \ln (2.26\times 10^{4})

\Delta G^o=-24839.406J/mole=-24.83\times 10^3J/mole=-24.83kJ/mole

Now we have to calculate the value of 'Q'.

The given balanced chemical reaction is,

CO(g)+2H_2(g)\rightarrow CH_3OH(g)

The expression for reaction quotient will be :

Q=\frac{(p_{CH_3OH})}{(p_{CO})\times (p_{H_2})^2}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q=\frac{(1.4)}{(1.2\times 10^{-2})\times (1.2\times 10^{-2})^2}

Q=8.1\times 10^{5}

Now we have to calculate the value of \Delta G_{rxn} by using relation (1).

\Delta G_{rxn}=\Delta G^o+RT\ln Q

Now put all the given values in this formula, we get:

\Delta G_{rxn}=-24.83kJ/mole+(8.314\times 10^{-3}kJ/mole.K)\times (298K)\ln (8.1\times 10^{5})

\Delta G_{rxn}=8.867\times 10^3J/mole=8.867kJ/mole

Therefore, the value of \Delta G_{rxn} is, 8.867kJ/mole

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2 years ago
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shtirl [24]

Answer:

C  U  M

Explanation:

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2 years ago
According to Newton's first law of motion what is required to make an object at rest move
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Pb has an atomic number of 82. It has an isotope Pb-207. The mass number is 207.
nikdorinn [45]

Answer:

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Explanation:

Given data:

Atomic number of Pb = 82

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Number of protons = ?

Solution:

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Number of neutrons = 207 - 82

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