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Lilit [14]
3 years ago
9

The mass of a watch glass was measured four times. The masses were

Chemistry
2 answers:
kenny6666 [7]3 years ago
5 0

Answer:

\large \boxed{\text{100.005 g}}

Explanation:

\text{Average mass} = \dfrac{\text{Sum of all measurements}}{\text{Number of measurements}}

1. Sum of Measurements

\begin{array}{cr}\textbf{No.}& \textbf{Mass/g} \\1& 99.997 \\2& 100.008 \\3& 100.011 \\4& 100.005 \\\text{Sum } = & \mathbf{400.021}\\\end{array}

2. Average mass

\text{Average mass} = \dfrac{\text{400.021 g}}{4} = \textbf{100.005 g}\\\\\text{The average mass of the watch glass is $\large \boxed{\textbf{100.005 g}}$}

tigry1 [53]3 years ago
4 0
To get the mass of the glass watch. It’s very simple. Take all 4 numbers 99.997, 100.008, 100.011, 100.005 add them together and then divide them by 4 bc there were 4 numbers to begin with.
The mass of the glass is- 100.00525 g
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In order to prepare 10 mL, 5 μM; <em> 2 mL of the 25 μM stock solution will be taken and diluted with water up to 10 mL mark.</em>

In order to prepare 10 mL, 10 μM; <em>4 mL of the 25 μM stock solution will be taken and diluted up to 10 mL mark.</em>

In order to prepare 10 mL, 15 μM; <em>6 mL of the 25 μM stock solution will be taken and diluted up to 10 mL mark.</em>

In order to prepare 10 mL, 20 μM; <em>8 mL of the 25 μM stock solution will be taken and diluted up to 10 mL mark.</em>

Explanation:

Using the dilution equation:

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Final molarity = 5 μM, final volume = 10 mL, initial molarity = 25 μM, initial volume = ?

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<em>2 mL of the 25 μM stock solution will be taken and diluted up to 10 mL mark.</em>

<em />

In order to prepare 10 mL, 10 μM from 25 μM stock,

25 x initial volume = 10 x 10

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<em>4 mL of the 25 μM stock solution will be taken and diluted up to 10 mL mark.</em>

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<em>6 mL of the 25 μM stock solution will be taken and diluted up to 10 mL mark.</em>

In order to prepare 10 mL, 20 μM from 25 μM stock,

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<em>8 mL of the 25 μM stock solution will be taken and diluted up to 10 mL mark.</em>

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