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Lilit [14]
3 years ago
9

The mass of a watch glass was measured four times. The masses were

Chemistry
2 answers:
kenny6666 [7]3 years ago
5 0

Answer:

\large \boxed{\text{100.005 g}}

Explanation:

\text{Average mass} = \dfrac{\text{Sum of all measurements}}{\text{Number of measurements}}

1. Sum of Measurements

\begin{array}{cr}\textbf{No.}& \textbf{Mass/g} \\1& 99.997 \\2& 100.008 \\3& 100.011 \\4& 100.005 \\\text{Sum } = & \mathbf{400.021}\\\end{array}

2. Average mass

\text{Average mass} = \dfrac{\text{400.021 g}}{4} = \textbf{100.005 g}\\\\\text{The average mass of the watch glass is $\large \boxed{\textbf{100.005 g}}$}

tigry1 [53]3 years ago
4 0
To get the mass of the glass watch. It’s very simple. Take all 4 numbers 99.997, 100.008, 100.011, 100.005 add them together and then divide them by 4 bc there were 4 numbers to begin with.
The mass of the glass is- 100.00525 g
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A 300-gallon anaerobic digester will be loaded daily with a feedstock that contains two parts dairy manure and one-part water by
Mars2501 [29]

Answer:

The volume of feedstock needed to mantain an organic load rate of 2 kgVS/day is 0.055 m3/day of feedstock.

The HRT is 20.6 days.

Explanation:

First, we calculate how many kg is 1 m3 of feedstock. We know the density, so we can calculate the mass:

M=\rho*V=37.5\frac{lb}{ft^3}*1m^3*(\frac{3.281ft}{1m})  ^3=1324.5lb=600.7 kg

If the VS are 6% in weight,

M_{vs}=0.06*M=0.06*600.7\,kg/m^3=36,0kgVS/m3

The volume per day needed to feed 2 kg of VS/day is:

V=\frac{2kg}{36kg/m^3}= 0.055m3/day=5.5litres/day

The HRT depends on the volume of the tank and the flow. Its equation is

HRT=\frac{V}{Q}=\frac{300gal}{0.055 m^3/day}*\frac{1m^3}{264.172gal}\\   \\HRT=20.6\,days

6 0
3 years ago
When there is an increase in temperature of a gas in an
Ahat [919]

Answer:increase In kinetic energy of molecules

Explanation:increase in kinetic energy of molecules

3 0
3 years ago
What is the maximum value of the secondary quantum number (l) allowed for atomic electrons with a principal quantum number n = 7
Elis [28]

Explanation:

Principal quantum number=n=7

Azimuthal quantum number=l:-

\\ \sf\longmapsto n-1

\\ \sf\longmapsto 7-1

\\ \sf\longmapsto \ell=6

3 0
3 years ago
Determine the partial negative charge on the bromine atom in a c−br bond. the bond length is 1.93 å and the bond dipole moment i
vaieri [72.5K]

Answer:

The value is x  =  0.151  \ e

Explanation:

From the question we are told that

The bond length is l  =  1.93\  \r  a =  1.93 *1 *10^{-10}  =1.93 *10^{-10}\  m

The bond dipole moment is \mu  = 1.40 d  = 1.40 *  3.33564 *10^{-30}  =  4.6699 *10^{-30} \  C \cdot m

Generally the dipole moment is mathematically represented as

\mu  =  Q *  l

Here Q is the partial negative charge on the bromine atom

So

Q =  \frac{\mu}{ l}

=> Q =  \frac{4.6699 *10^{-30}}{ 1.93 *10^{-10} }

=> Q = 2.42 *10^{-20} C

Generally

1 electronic charge(e) is equivalent to 1.60*10^{-19} C

So x electronic charge(e) is equivalent to Q = 2.42 *10^{-20} C

=> x  =  \frac{2.42 *10^{-20}}{1.60*10^{-19} }

=>     x  =  0.151  \ e

3 0
3 years ago
Electronegativity difference of F and Cl: <br><br> ionic<br><br> covalent
gulaghasi [49]

Answer: Electronegativity difference of F and Cl: 1.0 and is covalent

Explanation:

6 0
3 years ago
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