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Lilit [14]
3 years ago
9

The mass of a watch glass was measured four times. The masses were

Chemistry
2 answers:
kenny6666 [7]3 years ago
5 0

Answer:

\large \boxed{\text{100.005 g}}

Explanation:

\text{Average mass} = \dfrac{\text{Sum of all measurements}}{\text{Number of measurements}}

1. Sum of Measurements

\begin{array}{cr}\textbf{No.}& \textbf{Mass/g} \\1& 99.997 \\2& 100.008 \\3& 100.011 \\4& 100.005 \\\text{Sum } = & \mathbf{400.021}\\\end{array}

2. Average mass

\text{Average mass} = \dfrac{\text{400.021 g}}{4} = \textbf{100.005 g}\\\\\text{The average mass of the watch glass is $\large \boxed{\textbf{100.005 g}}$}

tigry1 [53]3 years ago
4 0
To get the mass of the glass watch. It’s very simple. Take all 4 numbers 99.997, 100.008, 100.011, 100.005 add them together and then divide them by 4 bc there were 4 numbers to begin with.
The mass of the glass is- 100.00525 g
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Alex17521 [72]

Answer:

C.) HOCl Ka=3.5x10^-8

Explanation:

In order to a construct a buffer of pH= 7.0 we need to find the pKa values of all the acids given below

we Know that

pKa= -log(Ka)

therefore

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=1.9208

B) similarly PKa of HF= -log(7.2 x 1 0^-4)= 2.7644

C)  pKa of HOCl= -log(3.5 x 1 0^-8)= 7.45

D) pKa of HCN = -log(4 x 1 0^-10)=  9.3979

If we consider the  Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution

The weak acid for making the buffer must have a pKa value near to the desired pH of the weak acid.

So, near to value, pH=7.0. , the only option is HOCl whose pKa value is 7.45.

Hence, HOCl will be chosen for buffer construction.

3 0
3 years ago
A regular 3-d spatial arrangement of points that correspond to atom positions within a crystal is called_______?
Soloha48 [4]

Answer:

Explanation:

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8 0
1 year ago
This happens in diffusion. Choose the correct answer(s)
svlad2 [7]
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2 years ago
The activation energy of a reaction is 56.9 kj/mol and the frequency factor is 1.5×1011/s. Part a calculate the rate constant of
Vanyuwa [196]

We will use Arrehenius equation

lnK = lnA  -( Ea / RT)

R = gas constant = 8.314 J / mol K

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ln A = ln (1.5×10 ^11) = 25.73

Ea = activation energy = 56.9 kj/mol = 56900 J / mol

lnK = 25.73 - (56900 / 8.314 X 298) = 2.76

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K = 15.8



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Answer:

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