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2 years ago

11

A solid cylinder having a diameter of 1.50 cm and a height of 5.15 cm has a mass of 95.56 g. Show the equations needed to calcul

ate the density of a solid.

1 answer:

Georgia [21]2 years ago

4 0

Answer:

you can solve the rest of the equation. I only reduced it to that much to show you how to derive it

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Write the formula for an isotope of oxygen with nine neutrons, including the mass number and the atomic number. Write the answer

Mumz [18]

The formula for an isotope of oxygen with nine neutrons, including the mass number and the atomic number is 17/8 O.

<h3>What is an isotope?</h3>

Isotope is any of two or more forms of an element where the atoms have the same number of protons, but a different number of neutrons within their nuclei.

This means that atoms of isotopes will have the same atomic number but a different mass number.

According to this question, an isotope of oxygen has 9 neutrons. If oxygen has an atomic number of 8, the formula of this particular isotope is as follows: 17/8 O.

Learn more about isotopes at: brainly.com/question/12955625

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2 years ago

Identify the conjugate base in each pairs

DiKsa [7]

Answer: 1) $RCOO^-$

2) $H_2PO_4^-$

3) $RNH_2$

4) $HCO_3^-$

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

1) $RCOOH\rightarrow RCOO^-+H^+$

Here, $RCOOH$ is loosing a proton, thus it is considered as an acid and after losing a proton, it forms $RCOO^-$ which is a conjugate base.

2) $H_3PO_4\rightarrow H_2PO_4^-+H^+$

Here, $H_3PO_4$ is loosing a proton, thus it is considered as an acid and after losing a proton, it forms $H_2PO_4^-$ which is a conjugate base.

3) $RNH_3^+\rightarrow RNH_2+H^+$

Here, $RNH_3^+$ is loosing a proton, thus it is considered as an acid and after losing a proton, it forms $RNH_2$ which is a conjugate base.

4) $H_2CO_3\rightarrow HCO_3^-+H^+$

Here, $H_2CO_3$ is loosing a proton, thus it is considered as an acid and after losing a proton, it forms $HCO_3^-$ which is a conjugate base.

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2 years ago

Which is the reason that ionic compounds are brittle? The bonds between the anions and cations are weak and therefore easily bro

bearhunter [10]

Well ionic compounds are brittle because similar charges repel, which causes them to break usually occurring when a force is applied, like a hammer strike.

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Rank these elements according to FIRST ionization energy, from highest to lowest:

Rzqust [24]

The trend of ionization energy in the periodic table is decreasing from right to left and from top to bottom. In this case, we are given with elements <span>K, Ca, Ge, Se, Br, Kr and see the periodic table to check the trend. The answer from highest to lowest Kr, Br, Se, Ge, Ca, and K</span>

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