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Bumek [7]
3 years ago
11

A solid cylinder having a diameter of 1.50 cm and a height of 5.15 cm has a mass of 95.56 g. Show the equations needed to calcul

ate the density of a solid.
Chemistry
1 answer:
Georgia [21]3 years ago
4 0

Answer:

you can solve the rest of the equation. I only reduced it to that much to show you how to derive it

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Name the organic molecule
tekilochka [14]

Answer:

hydrocarbons are the answer

6 0
3 years ago
Which of the following is not an example of a pure element?
motikmotik
Copper wire is not an example of a pure element because although it's made by pure elements, it's not one itself. It's made by factories.

Have a nice day! :)
8 0
3 years ago
Read 2 more answers
On the basis of electronegativity, which of these pairs of elements is most likely to form monatomic ions?
mixer [17]

Answer is: Cl and Na.

sodium and chlorine are in third period and they have very different properties. Sodium is solid metal and chlorine is gaseous nonmetal.

They form compound NaCl (Sodium chloride), because sodium lost one valence electron and form cation Na⁺, chlorine gain one electron and form anion Cl⁻.

Electron configuration of sodium atom: ₁₁Na 1s² 2s² 2p⁶ 3s¹.

Electron configuration of chlorine atom: ₁₇Cl 1s² 2s² 2p⁶ 3s² 3p⁵.

Other examples are metal-metal pairs and they do not form cation and anion.

8 0
3 years ago
Read 2 more answers
If 10.62 mL of a standard 0.3330 M KOH solution reacts with 98.20 mL of CH3COOH solution, what is the molarity of the acid solut
Nikolay [14]

Answer:

0.036 M of CH_{3} COOH

Explanation:

It is an example of acid-base neutralization reaction.

KOH  + CH_{3} COOH  ----> CH_{3} COO^{-} K^{+}   +   H_{2}O

Base           Acid                           Salt                                    

When two component react then the number of moles of both the component should be same, therefore the number of moles and acids and bases should be the same in the following .

Molarity= \frac{\textrm{No. of Moles}}{\textrm{Volume of the Particular Solution}}

No.of moles= Molarity × Volume of the Particular Solution

Therefore,

M_{1}V_{1} =M_{2}V_{2}------------------------------(1)

where

M_{1}= Molarity of Acid

V_{1}= Volume of Acid

M_{2}= Molarity of Base

V_{2}= Volume of Base

M_{1}=0.3330 M

V_{1}=10.62 mL

V_{2}=98.2 mL

M_{2}=??(in M)

Plugging in Equation 1,

0.3330 × 10.62 =M_{2}  × 98.2  

M_{2}=\frac{0.3330*10.62}{98.2}

M_{2}=0.036 M

3 0
3 years ago
How much water would I need to add to 500 ml of a 2.4 M KCL solution to make a 1.0 M solution
Yuki888 [10]

the answer is 700ml

5 0
3 years ago
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