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Bumek [7]
3 years ago
11

A solid cylinder having a diameter of 1.50 cm and a height of 5.15 cm has a mass of 95.56 g. Show the equations needed to calcul

ate the density of a solid.
Chemistry
1 answer:
Georgia [21]3 years ago
4 0

Answer:

you can solve the rest of the equation. I only reduced it to that much to show you how to derive it

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Ten kilograms of R-134a fill a 1.595-m3 weighted piston-cylinder device at a temperature of −26.4°C. The container is now heated
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Explanation:

The given data is as follows.

    Mass of refrigerant, m = 10 kg

  Volume of the refrigerant, V = 1.595 m^{3}

Formula for specific volume of the refrigerant is as follows.

        v = \frac{V}{m}

           = 0.1595 m^{3}/kg

So, at -26.4^{o}C specific volume will be within v_{f} and v_{g} and pressure is constant.

The fluid will be in super-heated state at temperature 100^{o}C and at T = -26.4^{o}C pressure 1 bar = 0.1 MPa.

According to super-heated tables, the specific volume is v = 0.30138 m^{3}/kg.

Hence, the final volume will be calculated as follows.

               V_{f} = v \times m

                         = 0.30138 m^{3}/kg \times 10 kg

                         = 3.0138 m^{3}

Thus, we can conclude that final volume of the R-134a is 3.0138 m^{3}.

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7. Which of the following does not use echolocation?
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A cupcake recipe designed to produce 18 cupcakes calls for 260 grams of
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Answer:

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Explanation:

Given data:

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Fluor required for 22 cupcakes,

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22 cupcake/18 cup cake×260 g = 317.7778 g

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