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Bumek [7]
3 years ago
11

A solid cylinder having a diameter of 1.50 cm and a height of 5.15 cm has a mass of 95.56 g. Show the equations needed to calcul

ate the density of a solid.
Chemistry
1 answer:
Georgia [21]3 years ago
4 0

Answer:

you can solve the rest of the equation. I only reduced it to that much to show you how to derive it

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Adjustment to environmental conditions is known as
alukav5142 [94]

Answer:

A.

Explanation:

Adjust = Adapt if that makes sense.

8 0
3 years ago
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Two litres of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 litres. How m
nlexa [21]

Answer:

The work done and heat absorbed are both -8,1 kJ

Explanation:

The work done in an isobaric process is defined as:

W = -P (Vf - Vi)

Where P is pressure ( 10 atm)

Vf = 10 L

Vi = 2 L

Thus, <em>W = -80 atm×L ≡ -8,1 kJ</em>

This is the work done in expansion of the gas.  As the gas remains at the same temperature, there is no change in internal energy doing that all work was absorbed as heat.

I hope it helps!

4 0
3 years ago
Which element(s) are not balanced in this equation?
poizon [28]
The correct response is A. Only the Fe is unbalanced.
6 0
3 years ago
Name a lustrous non- metal ?​
kogti [31]

Answer:

it is iodine it seems very right

5 0
3 years ago
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Calculate the amount of heat gained when one 250 gram bottle is heated from 25oC to 30oC. The specific heat of water is 4.18 J/g
Fed [463]

Answer:

5230J

Explanation:

Mass (m) = 250g

Initial temperature (T1) = 25°C

Final temperature (T2) = 30°C

Specific heat capacity (c) = 4.184J/g°C

Heat energy (Q) = ?

Heat energy (Q) = Mc∇T

Q = heat energy

M = mass of the substance

C = specific heat capacity

∇T = change in temperature = T2 - T1

Q = 250 × 4.184 × (30 - 25)

Q = 1046 ×5

Q = 5230J

The heat energy required to raise the temperature of 250g of water from 25°C to 30°C is 5230J

7 0
3 years ago
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