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Alex73 [517]
4 years ago
8

At room temperature, which of these are oxide minerals? Select all that apply.

Chemistry
2 answers:
DerKrebs [107]4 years ago
7 0
C. and d. are oxyminerals.
Klio2033 [76]4 years ago
3 0

Answer:  C.Al_{2}O_{3} and D.Fe_{3}O_{4}

Explanation: Oxide minerals are the minerals in which the oxide anion is bonded to the central metal atom. These are useful for industrial purposes.

Out of the given options, only two of them can be categorized as the oxide minerals.  

H2O and CO2 will not be considered as oxide minerals.

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If your unknow solid has an impurity that is insoluble in cyclohexane, will this impurity result in the molar mass of the unknow
ser-zykov [4K]

Answer:

High

Explanation:

When the unknown compound contains an impurity that is insoluble in cyclohexane, the solute will not dissolve in the solvent (cyclohexane) completely. ∆T of the solution would be smaller than it is supposed to be, when compared to a compound without such insoluble impurity. Molecular weight determination won't be accurate because the molecular weight obtained will be higher as a result of the fact that the mass of the solute would include the actual solute that is changing the temperature and the excess mass of the impurity.

5 0
3 years ago
What the approximate mass of 24cm of silver, if the density is 10.5 g/cm
Alona [7]
Use equation density = mass/volume
Known/Given

d= 10.5g/cm^3
v= 24.0 cm^3

Use that equation i just mentioned...
Solution
Rewrite the formula as the forumla for solving density into mass

Which is... mass = 10.5g/cm^3 × 24.0cm^3 = 252g

So thats the answer
252g

Hope i could help
8 0
3 years ago
A solution contains two isomers, n-propyl alcohol and isopropyl alcohol, at 25°C. The total vapor pressure is 38.6 torr. What ar
Leona [35]

Answer:

Mole fraction of alcohols in liquid phase x_1=0.2727\& x_2=0.7273.

Mole fraction of alcohols in vapor phase y_1=0.1468\& y_2=0.8516.

Explanation:

The total vapor pressure of the solution = p =38.6 Torr

Partial vapor pressure of the  n-propyl alcohol =p^{o}_1=21.0 Torr

Partial vapor pressure of the isopropyl alcohol =p^{o}_2=45.2 Torr

p=x_1\times p^{o}_1+x_2\times p^{o}_2  (Raoult's Law)

p=x_1\times p^{o}_1+(1-x_1)\times p^{o}_2

38.6 Torr=x_1\times 21.0 Torr+(1-x_1)\times 45.2 Torr

x_1=0.2727

x_2=1-0.2727=0.7273

x_1\& x_2 is mole fraction in liquid phase.

Mole fraction of components in vapor phase y_1\& y_2

p_1=y_1\times p (Dalton's law of partial pressure)

y_1=\frac{p_1}{38.6 Torr}=\frac{p^{o}_1\times x_1}{38.6 Torr}

y_1=\frac{21.0 Torr\times 0.2727}{38.6 Torr}=0.1468

y_1=\frac{p_2}{38.6 Torr}=\frac{p^{o}_2\times x_2}{38.6 Torr}

y_2=\frac{45.2 Torr\times 0.7273}{38.6 Torr}=0.8516

Mole fraction of alcohols in vapor phase y_1=0.1468\& y_2=0.8516

5 0
3 years ago
When 1.104 grams of iron metal are mixed with 26.023 grams of hydrochloric acid in a coffee cup calorimeter, the temperature ris
Alika [10]

Answer:

a) An exothermic reaction, will release heat. No heat will be absorbed.

b) 903.71 J  of heat released

c) reaction is exothermic and ∆H will be negative.

d) ΔHreaction = 818.6 J/g

e)  ΔHreaction = 45.6 kJ/mol

f) ΔHreaction = 91.2 kJ

Explanation:

<u>Step 1:</u> Data given

Mass of iron = 1.104 grams

Mass of hydrochloric acid = 26.023 grams

Initial temperature = 25.2°C

Final temperature = 33.5 °C

Temperature change = 8.3 °C

<u>Step 2:</u> The balanced equation

2Fe(s)+6HCl(aq) → 2FeCl3 (aq)+3H2 (g)

(A)  Determine the amount of heat (in J) absorbed by the reaction mixture.

Since we have a rise of temperature, this means the reaction is exothermic.

An exothermic reaction, will release heat. No heat will be absorbed.

(B)  How much heat (in J) was released by the reaction that occurred?

q = mC∆T

with q = heat released (in J)

with m = the mass (in grams)

with c = the specific heat capacity (in J/g°C)

with  ∆T  = The change in temperature (in °C)

q = (26.023g)*(4.184 J/g°C)*(8.3 °C) = 903.71 J  of heat released

(C)  Is this reaction exothermic or endothermic? Is ΔHreaction positive or negative?

Since we have a rise of temperature, this means the reaction is exothermic.

There is heat released so ∆H will be negative.

(D)  Under constant pressure conditions (as used in this experiment), the heat released by the reaction equals the reaction enthalpy, qreleased = ΔHreaction. Determine ΔHreaction in Joules per gram of metal used (J/g).

ΔHreaction = 903.71 J/1.104 g = 818.6 J/g

(E) Determine ΔHreaction in kilojoules per mole of metal used (kJ/mol)

Number of moles of iron =1.104 grams / 55.845 g/mol = 0.0198 moles

ΔHreaction = 903.71 J / 0.0198 moles = 45641.9 J/mol = 45.6 kJ/mol

(F)  Determine ΔHreaction in kilojoules per mole for the balanced reaction equation provided

Since we have 2moles of Fe in the balanced reaction;

ΔHreaction = 45.6 kJ/mol * 2 mol = 91.2 kJ

7 0
3 years ago
Brainiest if answered in the next 5m
bearhunter [10]
The equation is already balanced

2AgNO3 + MgCl2 => 2AgCl + Mg(NO3)2
7 0
4 years ago
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