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maw [93]
4 years ago
12

Janet wants to find the spring constant of a given spring, so she hangs the spring vertically and attaches a 0.63 kg mass to the

spring's other end. if the spring stretches 2.8 cm from its equilibrium position, what is the spring constant?
Physics
1 answer:
-Dominant- [34]4 years ago
3 0
<span>The spring constant F = kx. But The mass acting on the spring is given by F = mg. So we have F = mg = kx. So k = mg/x where m = 0.63kg and g = 9.81N and x = 2.8 cm = 0.028m. Then we have k = (0.63 * 9.81)/0.028 = 220.725N</span>
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uysha [10]

Answer: 88 m/s

Explanation:

If we are talking about an acceleration at a uniform rate, we are dealing with constant acceleration, hence we can use the following equation:

{V_{f}}^{2}={V_{o}}^{2}+2ad (1)

Where:

V_{f}=0 Is the final velocity of the plane (we know it is zero because we are told the pilot stops the plane at a specific distance)

V_{o} Is the initial velocity of the plane

a=-8m/s^{2} is the constant acceleration of the plane

d=484m is the distance at which the plane stops

Isolating  V_{o} from (1):

V_{o}=\sqrt{-2ad} (2)

V_{o}=\sqrt{-2(-8m/s^{2})(484m)} (3)

Finally:

V_{o}=88m/s This is the veocity the plane had before braking began

8 0
3 years ago
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Svet_ta [14]

The person walking down the sidewalk follows the newton's third law of motion.

Explanation:

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  • Another important force included in the walking mechanism is friction. With out friction one cannot walk down the sidewalks.
  • Hence the forces involved in the walking of a person down the sidewalk are:
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4 0
3 years ago
A rifle fires a 2.10 x 10^-2 kg pellet straight upward, because the pellet rests on a compressed spring when the trigger is is p
yKpoI14uk [10]

m = mass of pellet = 2.10 x 10⁻² kg

x = compression of spring at the time launch = 9.10 x 10⁻² m

h = height gained by the pellet above the initial position = 6.10 m

k = spring constant

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4 0
3 years ago
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Inessa05 [86]

Answer:

t = 1.09 s.

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This quadratic equation can be solved using determinant.

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Of course, we will choose the positive time.

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Explanation:

Im pretty sure im sorry if I am wrong

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