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maw [93]
4 years ago
12

Janet wants to find the spring constant of a given spring, so she hangs the spring vertically and attaches a 0.63 kg mass to the

spring's other end. if the spring stretches 2.8 cm from its equilibrium position, what is the spring constant?
Physics
1 answer:
-Dominant- [34]4 years ago
3 0
<span>The spring constant F = kx. But The mass acting on the spring is given by F = mg. So we have F = mg = kx. So k = mg/x where m = 0.63kg and g = 9.81N and x = 2.8 cm = 0.028m. Then we have k = (0.63 * 9.81)/0.028 = 220.725N</span>
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An explorer is caught in a whiteout (in which the snowfall is so thick that the ground cannot be distinguished from the sky) whi
Brrunno [24]

Answer:

The explorer should travel to reach base camp to 5.02 Km at 4.28° south of due west.

Explanation:

Using trigonometric function like Sen(Ф), Cos(Ф) and Tan(Ф) we can get distance and direction that the explorer should travel to reach base camp. When we discompound the vector X = 7.8*Cos(50) = 5.01 Km y y = 7.8 * Sen (50) - 5.6 = 5.975 - 5.6 (Km) = 0.375 (Km) so that Tan (\alpha ) = \frac{0.375}{5.01} = 4.28; \alpha = Arctang (\frac{0.375}{5.01}) = 4.28 (degree) to get how far we use Pythagorean theorem so R^{2} = x^{2}+y^{2} so that R=\sqrt{0.375^{2}+5.01^{2} } =5.02 (Km)

6 0
4 years ago
Read 2 more answers
What is the mass of an object that is accelerated at 25 m/s2 by a force of 135 N?
yKpoI14uk [10]

Answer:

<h3>The answer is 5.4 kg</h3>

Explanation:

The mass of the object can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{135}{25}   =  \frac{27}{5} \\

We have the final answer as

<h3>5.4 kg</h3>

Hope this helps you

4 0
3 years ago
A small ball is attached to the lower end of a 0.800-m-long string, and the other end of the string is tied to a horizontal rod.
mestny [16]

Answer:

a = 17.68 m/s²

Explanation:

given,

length of the string, L = 0.8 m

angle made with vertical, θ = 61°

time to complete 1 rev, t = 1.25 s

radial acceleration = ?

first we have to calculate the radius of the circle

 R = L sin θ

 R = 0.8 x sin 61°

 R = 0.7 m

now, calculating at the angular velocity

\omega =\dfrac{2\pi}{T}

\omega =\dfrac{2\pi}{1.25}

  ω = 5.026 rad/s

now, radial acceleration

 a = r ω²

 a = 0.7 x 5.026²

a = 17.68 m/s²

hence, the radial acceleration of the ball is equal to 17.68 rad/s²

7 0
4 years ago
A container contains 200g of water at initial temperature of 30°C. An iron nail of mass 200g at temperature of 50°C is immersed
d1i1m1o1n [39]

Answer:

Assuming there is no heat loss to the surrounding.

Heat lost by iron equals heat gained by water.

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x=31.94 °C

Explanation:

4 0
3 years ago
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Um corpo de massa 50g recebe 300 calorias e sua temperatura sobe de -10°C até 20°C. Determine a capacidade térmica do corpo e o
kykrilka [37]

The specific heat capacity of the substance is 0.963 J/g^{\circ}C

Explanation:

When an object of mass m is supplied with a certain amount of energy Q, its temperature increases according to the equation:

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m is the mass of the object

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\Delta T is the increase in temperature of the object

In this problem, we have

Q=300 cal \cdot 4.814 = 1444.2 J

m = 50 g

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Therefore, we can solve for C_s to find its specific heat capacity:

C_s = \frac{Q}{m\Delta T}=\frac{1444.2}{(50)(30)}=0.963 J/gC

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