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agasfer [191]
3 years ago
14

Ben is 9 years younger than his brother Jeff. in 10 years, the sum of their ages will be 67 how old are they now​

Mathematics
1 answer:
Eddi Din [679]3 years ago
8 0

Hey there! I'm happy to help!

Let's represent Ben's age with a B and Jeff's with a J in a few equations below.

B=J-9                               (Ben is 9 years younger than Jeff)

B+10+J+10=67                  (In 10 years, the sum of their ages will be 67)

We know that B is equal to J-9. So, in the second equation, we can replace B with J-9 to solve for J.

J-9+10+J+10=67

We combine like terms.

2J+11=67

We subtract 11 from both sides.

2J=56

We divide both sides by two.

J=28

And, we know that Ben is nine years younger than Jeff, so this means Ben is 19 years old.

Ben is 19 years old and Jeff is 28.

I hope that this helps! Have a wonderful day! :D

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2 years ago
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<em>(Please refer to the attached image for the table )</em>

Here we got, ∑x = 44 , ∑y = 183 , ∑x² = 362 , ∑y² = 6575 and ∑xy = 1480

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So, plugging those values into the above formula..........

r= \frac{n(\Sigma xy)-(\Sigma x)(\Sigma y)}{\sqrt{[n\Sigma x^2-(\Sigma x)^2][n\Sigma y^2-(\Sigma y)^2]}}\\ \\ r=\frac{7(1480)-(44)(183)}{\sqrt{[7(362)-(44)^2][7(6575)-(183)^2]}}\\ \\ r=\frac{10360-8052}{\sqrt{(598)(12536)}}\\ \\ r=\frac{2308}{\sqrt{7496528}}\\ \\ r=0.84

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3 years ago
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skad [1K]

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