$\cfrac{a}{sinA}= \cfrac{b}{sinB} \ \ \to \\ sinB= \cfrac{b*sinA}{a} = \cfrac{14*sin35^o}{12}= 0.6692 \ \ \to \ m \angle B=42^o \\ \\ \\ m \angle C=180- m \angle A- m \angle B=180-35-42=103^o \\ \\ \\ \cfrac{a}{sinA}= \cfrac{c}{sinC} \ \ \to \ c= \cfrac{a*sinC}{sinA}= \cfrac{12*sin103^o}{sin35^o} \approx 20.4$

6 0

3 years ago

Can someone help solve

leva [86]

$\frac{-18z^{7}y^{5}-9z^{9}y^4+18z^6y^8}{9zy^{2} }= -2z^6y^3-z^8y^2+2z^5y^6$

When variables with exponents are divided by each other, you subtract the exponents.

For example:

$\frac{x^2}{x^1} = x^{2-1} =x^1$

$\frac{x^5}{x^3} =x^{5-3} = x^2$

8 0

3 years ago

(4+7-1÷5)÷1.2+2.5×3-0.2

lawyer [7]

The final answer to tour problem 16.3

5 0

3 years ago

What is the distance between A (-4,2) and B (12,4)

My name is Ann [436]

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
A(\stackrel{x_1}{-4}~,~\stackrel{y_1}{2})\qquad
B(\stackrel{x_2}{12}~,~\stackrel{y_2}{4})\qquad \qquad
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AB=\sqrt{[12-(-14)]^2+[4-2]^2}\implies AB=\sqrt{(12+14)^2+(4-2)^2}
\\\\\\
AB=\sqrt{26^2+2^2}\implies AB=\sqrt{680}$

3 0

2 years ago

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