2 years ago

If x can be any number, how many solutions are there for the equation?

Mathematics

1 answer:

svlad2 [7]2 years ago

7 0

A. There are many solutions because there are many values for the variables that make the equation true.

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Four more than the quotient of a number and 3 is 9

barxatty [35]

The algebraic expression of "Four more than the quotient of a number and 3 is 9" is $\frac{x}{3}+4=9$

The value of x=15

Step-by-step explanation:

We need to express "Four more than the quotient of a number and 3 is 9" as algebraic expression.

Let the number = x

Solving:

quotient of a number and 3: $\frac{x}{3}$

Four more than the quotient of a number and 3: $\frac{x}{3}+4$

Four more than the quotient of a number and 3 is 9: $\frac{x}{3}+4=9$

Now, finding value of x:

$\frac{x}{3}+4=9\\Adding\,\,-4\,\,on\,\,both\,\,sides:\\\frac{x}{3}+4-4=9-4\\\frac{x}{3}=5\\Multiply\,\,both\,\,sides\,\,by\,\,3:\\x=5*3\\x=15$

So, value of x = 15

Keywords: Algebraic expression

Learn more about algebraic expression at:

#learnwithBrainly

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Download photo math and it will let you take a picture of the equation and answer it for you

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