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xz_007 [3.2K]
2 years ago
15

If you can, answer at least 2 question I put 10 points on it

Mathematics
1 answer:
igomit [66]2 years ago
8 0

Answer:

a) one solution(x = 9)

b) no solution

c) infinite solutions

Step-by-step explanation:

a) To solve this equation, we can add 4 on both sides in order to isolate x:

x - 4 =5

+ 4     + 4

x = 9

Since x equals 9, that counts as only one solution, as there is only one value of x that makes the equation true.

b) We start by subtracting 2x from both sides to combine the variable terms:

2x - 6 = 2x + 5

-2x         -2x

-6 = 5

The statement, -6 = 5 is never true and it is not dependent on the value of x. This means there are no solutions to this equation.

c) We can start by subtracting 3x from both sides to combine the terms with x:

3x + 12 = 3x + 12

-3x          -3x

12 = 12

The statement above is always true, and no matter the value of x, it will always be true. This means there are infinite solutions to the equation.

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What is. - 3 7/8 × - 4 3/5 help please
Yakvenalex [24]

Answer:

713/40 or as mixed fraction of 17 33/40 (see setps below)

Step-by-step explanation:

Simplify the following:

-(3 + 7/8) (-(4 + 3/5))

Hint: | Multiply all instances of -1 in -(3 + 7/8) (-(4 + 3/5)).

(-1)^2 = 1:

(4 + 3/5) (3 + 7/8)

Hint: | Put the fractions in 3 + 7/8 over a common denominator.

Put 3 + 7/8 over the common denominator 8. 3 + 7/8 = (8×3)/8 + 7/8:

(4 + 3/5) (8×3)/8 + 7/8

Hint: | Multiply 8 and 3 together.

8×3 = 24:

(4 + 3/5) (24/8 + 7/8)

Hint: | Add the fractions over a common denominator to a single fraction.

24/8 + 7/8 = (24 + 7)/8:

(4 + 3/5) (24 + 7)/8

Hint: | Evaluate 24 + 7 using long addition.

| 1 |  

| 2 | 4

+ | | 7

| 3 | 1:

(4 + 3/5)×31/8

Hint: | Put the fractions in 4 + 3/5 over a common denominator.

Put 4 + 3/5 over the common denominator 5. 4 + 3/5 = (5×4)/5 + 3/5:

31/8 (5×4)/5 + 3/5

Hint: | Multiply 5 and 4 together.

5×4 = 20:

((20/5 + 3/5)×31)/8

Hint: | Add the fractions over a common denominator to a single fraction.

20/5 + 3/5 = (20 + 3)/5:

31/8 (20 + 3)/5

Hint: | Evaluate 20 + 3.

20 + 3 = 23:

23/5×31/8

Hint: | Express 23/5×31/8 as a single fraction.

23/5×31/8 = (23×31)/(5×8):

(23×31)/(5×8)

Hint: | Multiply 5 and 8 together.

5×8 = 40:

(23×31)/40

Hint: | Multiply 23 and 31 together.

| 3 | 1

× | 2 | 3

| 9 | 3

6 | 2 | 0

7 | 1 | 3:

Answer: 713/40

________________________________________

Convert to a mixed number:

713/40

Hint: | Use long division to get a quotient and remainder.

Divide 713 by 40:

4 | 0 | 7 | 1 | 3

Hint: | How many times does 40 go into 71?

40 goes into 71 at most one time:

| | | 1 | |  

4 | 0 | 7 | 1 | 3 |  

| - | 4 | 0 | |  

| | 3 | 1 | 3 |  

Hint: | How many times does 40 go into 313?

40 goes into 313 at most 7 times:

| | | 1 | 7 |  

4 | 0 | 7 | 1 | 3 |  

| - | 4 | 0 | |  

| | 3 | 1 | 3 |  

| - | 2 | 8 | 0 |  

| | | 3 | 3 |  

Hint: | Summarize the results.

Read off the results. The quotient is the number at the top and the remainder is the number at the bottom:

| | | 1 | 7 | (quotient)

4 | 0 | 7 | 1 | 3 |  

| - | 4 | 0 | |  

| | 3 | 1 | 3 |  

| - | 2 | 8 | 0 |  

| | | 3 | 3 | (remainder)

Hint: | In the equivalent mixed fraction, the quotient becomes the whole number part, the remainder becomes the numerator part, and the divisor (denominator) remains the denominator.

The quotient of 713/40 is 17 with remainder 33, so:

Answer: 17 33/40

6 0
3 years ago
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