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leva [86]
3 years ago
15

Consider the following reactions. (Note: (s) = solid, (l) = liquid, and (g) = gas.)

Chemistry
1 answer:
Katarina [22]3 years ago
8 0

Answer:

B: endothermic

Hope this helps :)

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Upon combustion, a compound containing only carbon and hydrogen produces 2.67 g<img src="https://tex.z-dn.net/?f=CO_%7B2%7D" id=
Hoochie [10]

Answer:

\boxed{\text{CH$_{2}$}}

Explanation:

1. Calculate the mass of each element

\text{Mass of C} = \text{2.67 g } \text{CO}_{2}\times \dfrac{\text{12.01 g C}}{\text{44.01 g }\text{CO}_{2}}= \text{0.7286 g C}\\\\\text{Mass of H} = \text{1.10 g }\text{H$_{2}$O}\times \dfrac{\text{2.016 g H}}{\text{18.02 g } \text{{H$_{2}$O}}} = \text{0.1231 g H}

2. Calculate the moles of each element

\text{Moles of C = 0.7286 g C}\times\dfrac{\text{1 mol C}}{\text{12.01 g C }} = \text{0.060 67 mol C}\\\\\text{Moles of H = 0.1231 g H} \times \dfrac{\text{1 mol H}}{\text{1.008 g H}} = \text{0.1221 mol H}

3. Calculate the molar ratios

Divide all moles by the smallest number of moles.

\text{C: } \dfrac{0.06067}{0.06067}= 1\\\\\text{H: } \dfrac{0.1221}{0.06067} = 2.015

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4 years ago
Can you help me on chemistry
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Answer:

potentially

Explanation:

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Answer:If we dissolve NaF in water, we get the following equilibrium:

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20.0 g of sodium fluoride is dissolve in enough water to make 500.0 mL of solution. Calculate the pH of the solution. The  K_b of the fluoride ion is 1.4 × 10 −11 .

Step 1: List the known values and plan the problem.

Known

mass NaF = 20.0 g

molar mass NaF = 41.99 g/mol

volume solution = 0.500 L

K_b of F – = 1.4 × 10 −11

Unknown

pH of solution = ?

The molarity of the F − solution can be calculated from the mass, molar mass, and solution volume. Since NaF completely dissociates, the molarity of the NaF is equal to the molarity of the F − ion. An ICE Table (below) can be used to calculate the concentration of OH − produced and then the pH of the solution.

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