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2 years ago

Cân bằng phương trình Mg+HCl->MgCl2+H2 bằng phương pháp thăng bằng

Chemistry

1 answer:

nignag [31]2 years ago

8 0

quá trình oxi hóa: Mg0 -> Mg2+ + 2e-

quá trình khử: 2H+ + 2e- -> H2 (cần 2 H+ để tạo 1 H2)

----> chỉ cần thêm 2 vào trước HCl (vì H+ là do HCl cung cấp)

----> Mg + 2HCl -> MgCl2 + H2

yay :)

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Can someone please help me with my science research I kind of need help in a few things that I listed, I’m currently working on

dalvyx [7]

Answer:

For your first question, Curium does not occur naturally on Earth, meaning that it is not produced naturally on Earth. However, it can be formed in nuclear reactors.

For your second question, Curium has been used to provide power to electrical equipment used on space missions, but doesn't seem to be that important overall.

Explanation:

Hope this helped!

7 0

2 years ago

A reaction between substances Y and Z is

Anuta_ua [19.1K]

Answer : The value of activation energy for this reaction is 108.318 kJ/mol

Explanation :

The Arrhenius equation is written as:

$K=A\times e^{\frac{-Ea}{RT}}$

Taking logarithm on both the sides, we get:

$\ln k=-\frac{Ea}{RT}+\ln A$ ............(1)

where,

k = rate constant = $2.95\times 10^{-3}L/mol.s$

Ea = activation energy = ?

T = temperature = 435 K

R = gas constant = 8.314 J/K.mole

A = pre-exponential factor = $3.00\times 10^{+10}L/mol.s$

Now we have to calculate the value of rate constant by putting the given values in equation 1, we get:

$\ln (2.95\times 10^{-3}L/mol.s)=-\frac{Ea}{8.314J/K.mol\times 435K}+\ln (3.00\times 10^{10}L/mol.s)$

$Ea=108318.365J/mol=108.318kJ/mol$

Therefore, the value of activation energy for this reaction is 108.318 kJ/mol

3 0

3 years ago

(Someone please help!)

ElenaW [278]

Answer:

COLORS

Explanation:

i looked it up lol

5 0

2 years ago

Read 2 more answers

Which of the following is the most reactive?

mezya [45]

4. Rubidium

I believe :)

4 0

3 years ago

Consider the reaction. 2 Pb ( s ) + O 2 ( g ) ⟶ 2 PbO ( s ) An excess of oxygen reacts with 451.4 g of lead, forming 367.5 g of

Art [367]

Answer : The percent yield of the reaction is, 75.6 %

Solution : Given,

Mass of Pb = 451.4 g

Molar mass of Pb = 207 g/mole

Molar mass of PbO = 223 g/mole

First we have to calculate the moles of Pb.

$\text{ Moles of }Pb=\frac{\text{ Mass of }Pb}{\text{ Molar mass of }Pb}=\frac{451.4g}{207g/mole}=2.18moles$

Now we have to calculate the moles of $PbO$

The balanced chemical reaction is,

$2Pb(s)+O_2(g)\rightarrow 2PbO(s)$

From the reaction, we conclude that

As, 2 mole of $Pb$ react to give 2 mole of $PbO$

So, 2.18 mole of $Pb$ react to give 2.18 mole of $PbO$

Now we have to calculate the mass of $PbO$

$\text{ Mass of }PbO=\text{ Moles of }PbO\times \text{ Molar mass of }PbO$

$\text{ Mass of }PbO=(2.18moles)\times (223g/mole)=486.1g$

Theoretical yield of $PbO$ = 486.1 g

Experimental yield of $PbO$ = 367.5 g

Now we have to calculate the percent yield of the reaction.

$\% \text{ yield of the reaction}=\frac{\text{ Experimental yield of }PbO}{\text{ Theoretical yield of }PbO}\times 100$

$\% \text{ yield of the reaction}=\frac{367.5g}{486.1g}\times 100=75.6\%$

Therefore, the percent yield of the reaction is, 75.6 %

3 0

3 years ago