When the rabbit Dispose of the grass it ate it will give nutrients to the dirt to grow more grass
Explanation:
From the attached phase diagram, one can easily make out the phase in which water exists. Matter generally exists in three physical states which are solid, liquid and gas. Water is a unique compound that can exists in these three states at a given temperature and pressure.
From the attached phase diagram,
- point O is the triple point where the three phases of pure substance co-exists.
- The areas between the curves points at a single phase of matter. Y is a water vapor.
- The lines on the curve denotes two equilibrium phases. For example; X is a phase contain ice and melt water.
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Answer : The concentration of silver ion is, 
Explanation :
Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.
The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.
As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.
The given equilibrium reaction is,

The expression of
will be,
![K_{eq}=[Ag^+]^2[S^{2-}]](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5BAg%5E%2B%5D%5E2%5BS%5E%7B2-%7D%5D)
![2.4\times 10^{-4}=(2.5\times 110^{-1})^2[S^{2-}]](https://tex.z-dn.net/?f=2.4%5Ctimes%2010%5E%7B-4%7D%3D%282.5%5Ctimes%20110%5E%7B-1%7D%29%5E2%5BS%5E%7B2-%7D%5D)
![[S^{2-}]=3.8\times 10^{-3}M](https://tex.z-dn.net/?f=%5BS%5E%7B2-%7D%5D%3D3.8%5Ctimes%2010%5E%7B-3%7DM)
Therefore, the concentration of silver ion is, 
For a second order kinetics, the reaction rate expression would be
-r = -dCa / dt = kCa^2 where k is the reaction constant and Ca is the concentration of reactant A.
Integrating this from Cao to Caf, will have the expression,
1/Caf - 1/Cao = kt
Substituting the given values and calculating for k,
1/0.00650 - 1/0.0100 = k(100)
k = 0.538 / M-s