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Daniel [21]
3 years ago
10

Please help................​

Mathematics
1 answer:
alexira [117]3 years ago
8 0

Answer:

so 2^{8} equals 2x2x2x2x2x2x2x2

Step-by-step explanation:

Its that because when expanding Exponents, you always put the first number of the exponet first. like for example, 3^{2} , you put the three 2 times and multiply. 3x3

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A bag contains 4 white, 2 blue, and
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1/2 for red

2/3

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r+w=5/6

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What does x equal in 3(x-2)=-3
Maru [420]

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Step-by-step explanation:

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2 years ago
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In most microcomputers the addresses of memory locations are specified in hexadecimal. These addresses are sequential numbers th
iren [92.7K]

Considering that the addresses of memory locations are specified in hexadecimal.

a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ )  = 65536 memory locations

b) The range of hex addresses in a microcomputer with 4096 memory locations is ;  4095

<u>applying the given data </u>:

a) first step : convert FFFF₁₆ to decimal           ( note F₁₆ = 15 decimal )

( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )

= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )

=  61440 + 3840 + 240 + 15 = 65535

∴ the memory locations from  0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations

b) The range of hex addresses with a memory location of 4096

= 0000₁₆ to FFFF₁₆ =  0 to 4096

∴ the range = 4095

Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.

Learn more : brainly.com/question/18993173

6 0
2 years ago
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