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Fofino [41]
3 years ago
13

Many companies use a quality control technique called acceptance sampling to monitor incoming shipments of parts, raw materials,

and so on. In the electronics industry, component parts are commonly shipped from suppliers in large lots. Inspection of a sample of n components can be viewed as the n trials of a binomial experiment. The outcome for each component tested (trial) will be that the component is classified as good or defective. Reynolds Electronics accepts a lot from a particular supplier if the defective components in the lot do not exceed 1%. Suppose a random sample of five items from a recent shipment is tested.
a. Assume that 1% of the shipment is defective. Compute the probability that no items in the sample are defective.

b. Assume that 1% of the shipment is defective. Compute the probability that exactly one item in the sample is defective.

c. What is the probability of observing one or more defective items in the sample if 1% of the shipment is defective?

d. Would you feel comfortable accepting the shipment if one item was found to be defective? Why or why not?
Mathematics
1 answer:
blondinia [14]3 years ago
8 0

Answer:

A. 0.9510

B. 0.0480

C. 0.0490

D. No, I would not feel comfortable accepting the shipment if one item was found defective, because the probability is quite small to obtain 1 or more defective items.

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Tasha believes that she can rewrite the difference of 120 minus 36 as a product of the GCF of the two numbers and the difference
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Answer:

GCF = 12

For the values 36, 120:

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The factors of 36 are: 1, 2, 3, 4, 6, 9, 12, 18, 36

The factors of 120 are: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120

Then the greatest common factor is 12.



Pair Share:

The GCF of 120 and 36 is ======> 12

so, 120 – 36 can be written as:

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Answer: ========> Therefore, Tasha is correct






Hope that helps!!!! : )




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