3 is the answer to your question
Answer:
It is sensible heat- the amount of heat absorbed by 1 kg of water when heated at a constant pressure from freezing point 0 degree Celsius to the temperature of formation of steam i.e. saturation temperature
So it is given as - mass× specific heat × rise in temperature
i.e. 4.2 × T
4.2 × (100–0)
So it is 420kj
If you ask how much quantity of heat is required to convert 1 kg of ice into vapour then you have to add latent heat of fusion that is 336 kj/kg and latent heat of vaporization 2257 kj/kg (these two process occur at constant temperature so need to add rise in tempeature)
So it will be
Q= 1×336 + 1× 4.18 ×100 + 1× 2257
Q = 3011 kj
Or 3.1 Mj
Hope you got this!!!!!!
Answer:
Workdone = 600 Kilojoules
Explanation:
Given the following data:
Time = 8 seconds
Power = 75,000 Watts
Distance = 58 m
To find the work done;
Power can be defined as the energy required to do work per unit time.
Mathematically, it is given by the formula;
Thus, work done is given by the formula;
Workdone = power * time
Workdone = 75000 * 8
Workdone = 600,000 = 600 KJ
Answer:
Varíe sus entrenamientos. Para muchos atletas, los ejercicios funcionales son el nombre del juego. ...
Realice un seguimiento y mida su rendimiento durante el entrenamiento. ...
Haga de la hidratación adecuada una prioridad. ...
Dedique suficiente tiempo a la recuperación. ...
Entrena tu cerebro. ...
Alimente su cuerpo de la manera correcta. ...
Considere agregar algunos suplementos a su dieta.
Explanation:
