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Illusion [34]
3 years ago
7

Car 1 drives 35 mph to the east, and car 2 drives 50 mph to the west. From the frame of reference of car 1, what is the velocity

of car 2?
A. 85 mph west
B. 15 mph east
C. 85 mph east
D. 15 mph west
Physics
2 answers:
Sergio039 [100]3 years ago
4 0
The distance between the two cars is increasing at the rate of 85 mph.

A passenger in Car-1 says that he is at rest in his own frame of reference,
and Car-2 is moving away from him at 85 mph, toward the west.
Radda [10]3 years ago
3 0

Answer:

A. 85 mph west

Explanation:

Velocity of car 1 is given as

v_1 = 35 mph towards East

\vec v_1 = 35(-\hat i) mph

Velocity of car 2 is given as

v_2 = 50 mph towards West

\vec v_2 = 50 (\hat i) mph

Now we need to find the speed of car 2 with respect to the frame of car 1

so it is given as

\vec v_{21} = \vec v_2 - \vec v_1

now we will have

\vec v_{21} = 50 (\hat i) - 35 (-\hat i) = 85 \hat i

so the relative speed will be 85 mph towards West

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A dragster starts from rest and travels 1/4 mi in 6.80 s with constant acceleration. What is its velocity when it crosses the fi
Ahat [919]
<h2>Its velocity when it crosses the finish line is 117.65 m/s</h2>

Explanation:

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 0 m/s

        Acceleration, a = ?

        Time, t = 6.8 s    

        Displacement, s = 1/4 mi =    400 meters

     Substituting

                      s = ut + 0.5 at²

                      400 = 0 x 6.8 + 0.5 x a x 6.8²

                      a = 17.30 m/s²

Now we have equation of motion v = u + at

     Initial velocity, u = 0 m/s

     Final velocity, v = ?

     Time, t = 6.8 s

      Acceleration, a = 17.30 m/s²

     Substituting

                      v = u + at  

                      v = 0 + 17.30 x 6.8

                      v = 117.65 m/s

Its velocity when it crosses the finish line is 117.65 m/s

6 0
3 years ago
While traveling home at dusk, a motorcyclist gets on the highway and increases the combined mass (400 kg
alexdok [17]

The acceleration of one of those bugs is equal to 305mi/s.

<h3>Acceleration calculation</h3>

To calculate the insect's acceleration, the action and reaction force of the impact must be considered.

As the insect will hit the helmet, the force it hits is the same force it receives, so we can make the following expression:

                                          m_m \times a_m = m_b \times a_b

                                        550 \times 0.0027 = 5 \times 10^{-3} \times a_b

<em>Speed ​​has been converted to miles per second</em>

                                          a_b = 305 mi/s

So, the acceleration of one of those bugs is equal to 305mi/s.

Learn more about acceleration calculation: brainly.com/question/390784

8 0
2 years ago
41
ASHA 777 [7]

Answer:

16

Explanation:

6+10=16

the box will go forward but it will be a little harder.

6 0
3 years ago
Which topic are you most likely to find in a physics textbook?
Sliva [168]

Answer: C. electricity and magnetism  

Explanation:

5 0
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