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Illusion [34]
3 years ago
7

Car 1 drives 35 mph to the east, and car 2 drives 50 mph to the west. From the frame of reference of car 1, what is the velocity

of car 2?
A. 85 mph west
B. 15 mph east
C. 85 mph east
D. 15 mph west
Physics
2 answers:
Sergio039 [100]3 years ago
4 0
The distance between the two cars is increasing at the rate of 85 mph.

A passenger in Car-1 says that he is at rest in his own frame of reference,
and Car-2 is moving away from him at 85 mph, toward the west.
Radda [10]3 years ago
3 0

Answer:

A. 85 mph west

Explanation:

Velocity of car 1 is given as

v_1 = 35 mph towards East

\vec v_1 = 35(-\hat i) mph

Velocity of car 2 is given as

v_2 = 50 mph towards West

\vec v_2 = 50 (\hat i) mph

Now we need to find the speed of car 2 with respect to the frame of car 1

so it is given as

\vec v_{21} = \vec v_2 - \vec v_1

now we will have

\vec v_{21} = 50 (\hat i) - 35 (-\hat i) = 85 \hat i

so the relative speed will be 85 mph towards West

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A large sheet of charge has a uniform charge density of 9  μCm2. What is the electric field due to this charge at a point just
Alex73 [517]

Answer:

Explanation:

Surface charge density, σ = 9 μC/m² = 9 x 10^-6 C/m²

According to the Gauss theorem,

Electric field due to the sheet is given by

E = \frac {\sigma }{2\epsilon _{0}}

E = \frac{9\times 10^{-6}}{2\times 8.854\times 10^{-12}}

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Christina drives his moped 7 kilometers North. She stops for lunch and then drives 5 kilometers East. What distance did she cove
Mashutka [201]

Answer:

She covers the distance is 12 km.

The magnitude of displacement is 8.6 km.

The direction of her displacement is north east.

Explanation:

Given that,

Christina drives his moped 7 kilometers North and stop for lunch and then drive 5 km east.

We need to calculate the total distance

Using formula of distance

d=d_{1}+d_{2}

Put the value into the formula

d=7+5

d=12\ km

We need to calculate the magnitude of displacement

Using formula of displacement

D=xi+yj

D=5i+7j

D=\sqrt{5^2+7^2}

D= 8.6\ km

The direction of her displacement is north east.

Hence, She covers the distance is 12 km.

The magnitude of displacement is 8.6 km.

The direction of her displacement is north east.

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