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den301095 [7]
3 years ago
9

Can anyone plz solve this for me?

Mathematics
1 answer:
NeX [460]3 years ago
7 0

y = mx + b

When x = 0, b is what is left on the right hand side of the equation. So the point is (0,b). This is more commonly called the y intercept. For example

y = 4x + 6

When x is 0 you get

y = 4(0) + 6

y = 0  + 6

y = 6

So in this case 6 is the y intercept. and the equation becomes y = 4x + 6

Answer: y intercept

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vovangra [49]
Multiply it by 3.
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6 0
3 years ago
Which graph represents the solution to the given system? y=5x+4; y=5x-3
Mars2501 [29]

Hello from MrBillDoesMath!

Answer:

The lines do not intersect


Discussion:

Where do the lines intersect?

5x + 4 = 5x - 3     =>                   subtract 5x from both sides

4         =       -3      =>  NO WAY! The lines do not intersect


Thank you,

MrB

3 0
3 years ago
Rewrite the following linear equation to slope form :y+2=7(2x-4)
garik1379 [7]

Answer:

y = 14x -30

Step-by-step explanation:

The slope intercept form is:

y = mx + b,

Slope intercept form is useful for finding the slope and y intercept of a line, hence why it is called "slope intercept" because it is easy to see the slope and the y intercept of a line in this form. Since the slope denoted by m, and y intercept denoted by b are clearly given.

y + 2 = 7(2x - 4)

Distribute 7 across the parentheses by multiplying x and 2x and 4 by 7.

y+2 = 14x - 28

subtract 2 from both sides. This cancels the 2 on the left and moves it to the right, while keeping the equation balanced.

y+2 -2 = 14x - 28 -2

y  = 14x - 30

y = 14x -30

As you can see our y = 14x -30 now looks like the point slope equation we had above. m = 14, and  b = -30. This means the line goes up 14 for every single unit you move to the right, and intersects the y axis at  (0, -30).

Please mark me brainliest.

4 0
3 years ago
Give the intervals where f(x) is concave up. (enter your answer using interval notation. if an answer does not exist, enter dn
Kipish [7]
Concave up is U-shaped.
There will be a inflection/critical point f'(x) =0 then a negative slope f'(x) = neg then another inflection/critical point f'(x) =0 at the bottom of the U-shape then a positive slope to last inflection/critical point. The interval for the Concave Up shape is the first and last inflection points.
6 0
3 years ago
Plss answer it correctly...I need asap​
lina2011 [118]

Answer:

sorry I cannot understand that

4 0
2 years ago
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