2x+5=x-8
-x on both sides
x+5=8
-5 on both sides
x=-13
Let's do this in steps, show your work!
<u>#1. We need to move all terms to one side.</u>
<u>x^2 - 7x = 0</u>
<u>#2. Then factor out the common term x.</u>
<u>x(x - 7) = 0.</u>
<u>#3. Simplify to get..</u>
<u>x = 0, 7.</u>
<u />
If you need help with any other question let me know.
<u />
Given:

To find:
The value of f'(x).
Solution:
Formulae used:



Chain rule:
![\dfrac{d}{dx}[f(g(x))]=f'(g(x))g'(x)](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7Bdx%7D%5Bf%28g%28x%29%29%5D%3Df%27%28g%28x%29%29g%27%28x%29)
Where C is an arbitrary constant.
We have,

Differentiate with respect to x.


Therefore, the required values is
.
No 12.14 is not bigger than 12.44
12.14 < 12.44
The distance is increasing at a rate that is the speed of the plane multiplied by the cosine of the angle between its flight path and the direct line to the radar station. That cosine is 4/√(3²+4²) = 4/5, so the distance is increasing at
440 mi/h × 4/5 = 352 mi/h